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Re: st: RE: plotting time series
From
stef salvez <[email protected]>
To
[email protected]
Subject
Re: st: RE: plotting time series
Date
Sat, 2 Jun 2012 20:22:55 +0100
Nick,
I omitted the /// because if I type
scatter two dFrance || scatter one dItaly || ///
look what stata tells me
/ / / is not a twoway plot type
r(198);
Is there any problem with my stata software?
On 6/2/12, Nick Cox <[email protected]> wrote:
> That's not a command. You omitted the /// which signal that the next
> line is a continuation. Look again at
>
> scatter two dFrance || scatter one dItaly || ///
> scatter two t2, ms(none) mla(dF2) mlabpos(12) || ///
> scatter one t1 , ms(none) mla(dI2) mlabpos(12) ///
> yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)
>
>
> On Sat, Jun 2, 2012 at 7:43 PM, stef salvez <[email protected]>
> wrote:
>> Nick thank you very much indeed.
>>
>> In Stata the command
>>
>> yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)
>>
>> does not work as I get the warning message
>>
>> unrecognized command: yla
>> r(199);
>>
>> Similarly for xla. I am so close to getting the desired plot!.Please
>> help!!!!
>>
>>
>>
>>
>> On 6/2/12, Nick Cox <[email protected]> wrote:
>>> On a second reading I think I understood better. This may help:
>>>
>>> clear
>>> input str8 (France Italy)
>>> "22/02/09" "14/06/09
>>> "22/03/09" "12/7/09
>>> "19/04/09" "9/8/09
>>> "17/05/09" "6/9/09"
>>> "12/7/09" "4/10/09"
>>> "09/08/09" "01/11/09"
>>> "6/9/09" "29/11/09"
>>> "4/10/09" "27/12/09"
>>> "01/11/09" "31/01/10"
>>> "29/11/09" "28/02/10"
>>> "27/12/09" "28/03/10"
>>> "31/01/10" "1/5/10"
>>> end
>>> gen dFrance = date(France, "DM20Y")
>>> gen dItaly = date(Italy, "DM20Y")
>>> gen dF2 = dFrance - dFrance[_n-1]
>>> gen dI2 = dItaly - dItaly[_n-1]
>>> gen t2 = (dFr + dFr[_n-1]) / 2
>>> gen t1 = (dIt + dIt[_n-1]) / 2
>>> gen two = 2
>>> gen one = 1
>>> scatter two dFrance || scatter one dItaly || ///
>>> scatter two t2, ms(none) mla(dF2) mlabpos(12) || ///
>>> scatter one t1 , ms(none) mla(dI2) mlabpos(12) ///
>>> yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)
>>>
>>>
>>> On Sat, Jun 2, 2012 at 5:56 PM, Nick Cox <[email protected]> wrote:
>>>> Sorry, I don't think I have a good understanding of what you want
>>>> here. In any case, adding lines can't add to information on spacing
>>>> that is not already shown on the graph.
>>>>
>>>> Nick
>>>>
>>>> On Sat, Jun 2, 2012 at 5:42 PM, stef salvez <[email protected]>
>>>> wrote:
>>>>> thank you NIck. It worked
>>>>>
>>>>> Let me explained what I did in order to tell you what I eventually
>>>>> need
>>>>>
>>>>> The MS excel file is the following
>>>>>
>>>>> have these sequence of dates in an excel file. The structure of the
>>>>> excel file is
>>>>> France Italy ......
>>>>> 22/02/09 14/06/09
>>>>> 22/03/09 12/7/2009
>>>>> 19/04/09 9/8/2009
>>>>> 17/05/09 6/9/2009
>>>>> 12/7/2009 4/10/2009
>>>>> 09/08/09 01/11/09
>>>>> 6/9/2009 29/11/09
>>>>> 4/10/2009 27/12/09
>>>>> 01/11/09 31/01/10
>>>>> 29/11/09 28/02/10
>>>>> 27/12/09 28/03/10
>>>>> 31/01/10
>>>>>
>>>>>
>>>>> The I apply the commands
>>>>>
>>>>> clear
>>>>> set trace off
>>>>> set more off
>>>>> set mem 120m
>>>>> cd d:\
>>>>> insheet using "dates0.csv"
>>>>> gen edate1 = date(v1, "DMY")
>>>>> gen edate2 = date(v2, "DMY")
>>>>>
>>>>> format edate1 %
>>>>> format edate2 %
>>>>> stripplot edate1 edate2
>>>>>
>>>>> and I get the desired plot. Yet the problem is that I also want to add
>>>>> on the top of each of these 2 lines the distance ( measured in days)
>>>>> between these successive dates for each country. And mark each
>>>>> distance with a symbol like { or [. Is is possible to extend the
>>>>> stripplot command somehow to achieve the desired resuls?
>>>>> thanks again
>>>>>
>>>>>
>>>>> Is it possible to add on the top of each of these 2 lines the
>>>>> distance ( measured in days) between these successive dates for each
>>>>> country. I would be grateful to you if you could also mark each
>>>>> distance with a symbol like { or [. I know it is a big challenge to
>>>>> you but for me is an impossible task
>>>>>
>>>>> thanks again
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> On 6/1/12, Nick Cox <[email protected]> wrote:
>>>>>> Have a look at -stripplot- from SSC.
>>>>>>
>>>>>> Nick
>>>>>> [email protected]
>>>>>>
>>>>>> stef salvez
>>>>>>
>>>>>> I have a panel data across countries and individuals. For each
>>>>>> country
>>>>>> I have a sequence of dates
>>>>>> For France for example
>>>>>> 22/02/09
>>>>>> 22/03/09
>>>>>> 19/04/09
>>>>>> 17/05/09
>>>>>> 12/07/09
>>>>>> 09/08/09
>>>>>> 06/09/09
>>>>>> 04/10/09
>>>>>> 01/11/09
>>>>>> 29/11/09
>>>>>> 27/12/09
>>>>>> 31/01/10
>>>>>>
>>>>>> For Italy
>>>>>> 14/06/09
>>>>>> 12/07/09
>>>>>> 09/08/09
>>>>>> 06/09/09
>>>>>> 04/10/09
>>>>>> 01/11/09
>>>>>> 29/11/09
>>>>>> 27/12/09
>>>>>> 31/01/10
>>>>>> 28/02/10
>>>>>> 28/03/10
>>>>>>
>>>>>> And I want to "plot" (in one graph) these sequences of dates in the
>>>>>> sense that I want to have a"visual" contact of each of the behaviour
>>>>>> of the series of dates because as you can see I do not have the same
>>>>>> start date and end date and the next date is not always every 28
>>>>>> days. So I have a jump in some cases. I would like to visualize these
>>>>>> characteristics-differences between the two series of dates by
>>>>>> making a plot.
>>>
>>> *
>>> * For searches and help try:
>>> * http://www.stata.com/help.cgi?search
>>> * http://www.stata.com/support/statalist/faq
>>> * http://www.ats.ucla.edu/stat/stata/
>>>
>>
>> *
>> * For searches and help try:
>> * http://www.stata.com/help.cgi?search
>> * http://www.stata.com/support/statalist/faq
>> * http://www.ats.ucla.edu/stat/stata/
>
> *
> * For searches and help try:
> * http://www.stata.com/help.cgi?search
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
* For searches and help try:
* http://www.stata.com/help.cgi?search
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/