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Re: st: RE: plotting time series


From   Nick Cox <[email protected]>
To   [email protected]
Subject   Re: st: RE: plotting time series
Date   Sat, 2 Jun 2012 20:01:47 +0100

That's not a command. You omitted the /// which signal that the next
line is a continuation. Look again at

scatter two dFrance || scatter one dItaly || ///
scatter two t2, ms(none) mla(dF2) mlabpos(12) || ///
scatter one t1 , ms(none) mla(dI2) mlabpos(12) ///
yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)


On Sat, Jun 2, 2012 at 7:43 PM, stef salvez <[email protected]> wrote:
> Nick thank you very much indeed.
>
> In Stata the command
>
> yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)
>
> does not work as I get the warning message
>
> unrecognized command:  yla
> r(199);
>
> Similarly for xla. I am so close to getting the desired plot!.Please help!!!!
>
>
>
>
> On 6/2/12, Nick Cox <[email protected]> wrote:
>> On a second reading I think I understood better. This may help:
>>
>> clear
>> input str8 (France              Italy)
>> "22/02/09"        "14/06/09
>> "22/03/09"       "12/7/09
>> "19/04/09"        "9/8/09
>> "17/05/09"                "6/9/09"
>> "12/7/09"       "4/10/09"
>> "09/08/09"        "01/11/09"
>> "6/9/09"         "29/11/09"
>> "4/10/09"       "27/12/09"
>> "01/11/09"       "31/01/10"
>> "29/11/09"        "28/02/10"
>> "27/12/09"        "28/03/10"
>> "31/01/10"        "1/5/10"
>> end
>> gen dFrance = date(France, "DM20Y")
>> gen dItaly = date(Italy, "DM20Y")
>> gen dF2 = dFrance - dFrance[_n-1]
>> gen dI2 = dItaly - dItaly[_n-1]
>> gen t2 = (dFr + dFr[_n-1]) / 2
>> gen t1 = (dIt + dIt[_n-1]) / 2
>> gen two = 2
>> gen one = 1
>> scatter two dFrance || scatter one dItaly || ///
>> scatter two t2, ms(none) mla(dF2) mlabpos(12) || ///
>> scatter one t1 , ms(none) mla(dI2) mlabpos(12) ///
>> yla(1 "Italy" 2 "France", ang(h)) xla(, format(%td)) legend(off)
>>
>>
>> On Sat, Jun 2, 2012 at 5:56 PM, Nick Cox <[email protected]> wrote:
>>> Sorry, I don't think I have a good understanding of what you want
>>> here. In any case, adding lines can't add to information on spacing
>>> that is not already shown on the graph.
>>>
>>> Nick
>>>
>>> On Sat, Jun 2, 2012 at 5:42 PM, stef salvez <[email protected]>
>>> wrote:
>>>> thank you NIck. It worked
>>>>
>>>> Let me explained what I did in order to tell you what I eventually need
>>>>
>>>> The MS excel file is the following
>>>>
>>>> have these sequence of dates in an excel file. The structure of the
>>>> excel file is
>>>> France              Italy                        ......
>>>> 22/02/09               14/06/09
>>>>  22/03/09       12/7/2009
>>>> 19/04/09        9/8/2009
>>>> 17/05/09                6/9/2009
>>>> 12/7/2009       4/10/2009
>>>>  09/08/09        01/11/09
>>>> 6/9/2009                29/11/09
>>>> 4/10/2009       27/12/09
>>>>  01/11/09       31/01/10
>>>> 29/11/09              28/02/10
>>>> 27/12/09              28/03/10
>>>> 31/01/10
>>>>
>>>>
>>>>  The I apply the commands
>>>>
>>>> clear
>>>> set trace off
>>>> set more off
>>>> set mem 120m
>>>> cd d:\
>>>> insheet using "dates0.csv"
>>>> gen edate1 = date(v1, "DMY")
>>>> gen edate2 = date(v2, "DMY")
>>>>
>>>> format edate1  %
>>>> format edate2  %
>>>> stripplot edate1 edate2
>>>>
>>>> and I get the desired plot. Yet the problem is that I also want to add
>>>> on the top of each of these 2 lines the distance ( measured in days)
>>>> between these successive dates for each country.  And mark each
>>>> distance with a symbol like { or [. Is is possible to extend the
>>>> stripplot command somehow to achieve the desired resuls?
>>>> thanks again
>>>>
>>>>
>>>>  Is it possible to add on the top of each of these 2 lines the
>>>> distance ( measured in days) between these successive dates for each
>>>> country. I would be grateful to you if you could also mark each
>>>> distance with a symbol like { or [. I know it is a big challenge to
>>>> you but for me is an impossible task
>>>>
>>>> thanks again
>>>>
>>>>
>>>>
>>>>
>>>> On 6/1/12, Nick Cox <[email protected]> wrote:
>>>>> Have a look at -stripplot- from SSC.
>>>>>
>>>>> Nick
>>>>> [email protected]
>>>>>
>>>>> stef salvez
>>>>>
>>>>> I have a panel data across countries and individuals. For each country
>>>>>  I have a sequence of dates
>>>>> For France for example
>>>>> 22/02/09
>>>>> 22/03/09
>>>>> 19/04/09
>>>>> 17/05/09
>>>>> 12/07/09
>>>>> 09/08/09
>>>>> 06/09/09
>>>>> 04/10/09
>>>>> 01/11/09
>>>>> 29/11/09
>>>>> 27/12/09
>>>>> 31/01/10
>>>>>
>>>>> For Italy
>>>>> 14/06/09
>>>>> 12/07/09
>>>>> 09/08/09
>>>>> 06/09/09
>>>>> 04/10/09
>>>>> 01/11/09
>>>>> 29/11/09
>>>>> 27/12/09
>>>>> 31/01/10
>>>>> 28/02/10
>>>>> 28/03/10
>>>>>
>>>>> And I want to "plot" (in one graph) these sequences of dates in the
>>>>> sense that I want to have a"visual" contact of each of the behaviour
>>>>> of  the series of dates because as you can see I do not have the same
>>>>> start date and   end date and the next date is not always every 28
>>>>> days. So I have a jump in some cases. I would like to visualize these
>>>>> characteristics-differences between the two  series of  dates by
>>>>> making a plot.
>>
>> *
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>>
>
> *
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