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RE: st: RE: submatrix
From
Nick Cox <[email protected]>
To
"'[email protected]'" <[email protected]>
Subject
RE: st: RE: submatrix
Date
Tue, 15 Nov 2011 12:14:32 +0000
Use Mata: e.g.
: y = (1::81)
: y2 = rowshape(y,9)
: y2
1 2 3 4 5 6 7 8 9
+----------------------------------------------+
1 | 1 2 3 4 5 6 7 8 9 |
2 | 10 11 12 13 14 15 16 17 18 |
3 | 19 20 21 22 23 24 25 26 27 |
4 | 28 29 30 31 32 33 34 35 36 |
5 | 37 38 39 40 41 42 43 44 45 |
6 | 46 47 48 49 50 51 52 53 54 |
7 | 55 56 57 58 59 60 61 62 63 |
8 | 64 65 66 67 68 69 70 71 72 |
9 | 73 74 75 76 77 78 79 80 81 |
+----------------------------------------------+
Nick
[email protected]
behailu ayele
Is there anyway, then, I can actually restructure my initial matrix in
a way that it has the dimensions I want (9 by 9) instead of one single
row?
On 11/15/11, Nick Cox <[email protected]> wrote:
> Yes; Stata can only regard it as an error if you refer to rows and/or
> columns that don't exist.
behailu ayele
> Thanks very much. I now went to matrix extraction and I think know my
> problem, now. My estimation result reads only as row. Whatever I want
> to extract,, it works when I specify as one row and any number of
> columns. What I mean is, it works when I do either of these:
>
> matrix A = b[1, "b1".."b9"]
>
> matrix A = b[1, "a1".."a9"]
>
>
> but it says conformability error whenever I do
>
> matrix A = b[1..2, "a1".."a9"]
>
>
> I am thinking I need to restructure my estimation result such that it
> is a proper matrix to begin with (with 9 by 9 dimension) and not just
> a matrix with one row and several columns.
>
> Thankyou again.
>
> behailu
>
>
> On 11/15/11, Nick Cox <[email protected]> wrote:
>> This is covered by the help on -matrix extraction-
>>
>> matrix new = b[1..9, 7..9]
>>
>> The = operator for assignment should be used (not ==).
>>
>> Nick
>> [email protected]
>>
>> behailu ayele
>>
>> I have problem extracting parts of a matrix I estimated.
>>
>> my matrix e(b) is 9 by 9. Now I want to extract the first line and I did
>> this.
>>
>> matrix b=e(b)
>> and then
>> matrix new==b[1,1..9]
>>
>> my problem is when i want to have a 3 by 9 matrix of the last three
>> columns
>>
>> is this not what I am supposed to do?
>>
>> matrix new==b[7/9,1..9]
>
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