Re: st: RE: submatrix

[behailu ayele <bbezabih@googlemail.com>]

Nick,

Thanks very much. I now went to matrix extraction and I think know my
problem, now. My estimation result reads only as row. Whatever I want
to extract,, it works when I specify as one row and any number of
columns. What I mean is, it works when I do either of these:

matrix A = b[1, "b1".."b9"]

matrix A = b[1, "a1".."a9"]


but it says conformability error whenever I do

matrix A = b[1..2, "a1".."a9"]


I am thinking I need to restructure my estimation result such that it
is a proper matrix to begin with (with 9 by 9 dimension) and not just
a matrix with one row and several columns.

Thankyou again.

behailu


On 11/15/11, Nick Cox <n.j.cox@durham.ac.uk> wrote:
> This is covered by the help on -matrix extraction-
>
> matrix new = b[1..9, 7..9]
>
> The = operator for assignment should be used (not ==).
>
> Nick
> n.j.cox@durham.ac.uk
>
> behailu ayele
>
> I have problem extracting parts of a matrix I estimated.
>
> my matrix e(b) is  9 by 9. Now I want to extract the first line and I did
> this.
>
> matrix b=e(b)
> and then
>  matrix new==b[1,1..9]
>
> my problem is  when i want to have a 3 by 9 matrix of the last three columns
>
> is this not what I am supposed to do?
>
> matrix new==b[7/9,1..9]
>
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