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Re: st: Storing output from a loop in only one variable
From
Eric Booth <[email protected]>
To
"<[email protected]>" <[email protected]>
Subject
Re: st: Storing output from a loop in only one variable
Date
Thu, 8 Jul 2010 15:41:06 +0000
<>
I think you just want:
gen x = .
foreach a in `range' {
replace x = `a' if !mi(`a') & mi(`x')
}
Unless I am not understanding your description (if not, an example with some sample data would be useful)
Also, note that your loop:
scalar i=1
foreach a in {range} {
...
gen x={output} in i
i++ //or i=i+1
}
would not work because you are asking Stata to re-generate "x" each time it passes through the loop.
~ Eric
__
Eric A. Booth
Public Policy Research Institute
Texas A&M University
[email protected]
Office: +979.845.6754
On Jul 8, 2010, at 10:32 AM, Dani Tilley wrote:
> Hi,
>
> I'm trying to store certain output in a new variable while I loop through
> different categories. At the end I want to average what I've stored and perhaps
> do some other manipulations. Right now, my code looks like this:
>
> foreach a in {range} {
> ...
> gen x`a'={output} in 1
> ...
> }
>
> su x*, mean
> di r(mean)
> drop x*
>
> So I create `a' variables that have the desired output as their 1st observations
> and N-1 missing points. I then average across these variables and drop them.
> While this gets the job done, I feel it's very clumsy. I'm looking to create a
> single variable, x, that will hold all `a' outputs. Something like
>
> scalar i=1
> foreach a in {range} {
> ...
> gen x={output} in i
> i++ //or i=i+1
> }
>
> Thanks,
> DF Tilley
>
>
>
>
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