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st: Re: Storing output from a loop in only one variable
From
Dani Tilley <[email protected]>
To
stata <[email protected]>
Subject
st: Re: Storing output from a loop in only one variable
Date
Thu, 8 Jul 2010 09:16:26 -0700 (PDT)
Hi Eric,
Thanks for your reply. Unfortunately, this doesn't give me what I'm looking for.
With the correction you pointed below, I get an x variable that only has the
output from the first loop on ALL its entries. I'm rather looking for a variable
that has -a- entries (the output from each loop on each line) and -N-a- missing
values.
Incidentally, could anyone tell me why I'm getting this error:
gen x=.
gen int t=2
replace x=123 in t
't' invalid obs no
r(198);
what is a valid obs no apart from actual integers plugged in? If I can figure
out a way to generate a variable that would not trigger this error, I can then
replace var=var+i and solve the problem I have.
Thanks,
Dani
----- Original Message ----
<>
Sorry, that should be "x", not "`x'" in the line:
> replace x = `a' if !mi(`a') & mi(`x')
~ Eric
From: Dani Tilley <[email protected]>
To: stata <[email protected]>
Sent: Thu, July 8, 2010 11:32:19 AM
Subject: Storing output from a loop in only one variable
Hi,
I'm trying to store certain output in a new variable while I loop through
different categories. At the end I want to average what I've stored and perhaps
do some other manipulations. Right now, my code looks like this:
foreach a in {range} {
...
gen x`a'={output} in 1
...
}
su x*, mean
di r(mean)
drop x*
So I create `a' variables that have the desired output as their 1st observations
and N-1 missing points. I then average across these variables and drop them.
While this gets the job done, I feel it's very clumsy. I'm looking to create a
single variable, x, that will hold all `a' outputs. Something like
scalar i=1
foreach a in {range} {
...
gen x={output} in i
i++ //or i=i+1
}
Thanks,
DF Tilley
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