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Re: st: Storing output from a loop in only one variable
From
Eric Booth <[email protected]>
To
"<[email protected]>" <[email protected]>
Subject
Re: st: Storing output from a loop in only one variable
Date
Thu, 8 Jul 2010 15:45:09 +0000
<>
Sorry, that should be "x", not "`x'" in the line:
> replace x = `a' if !mi(`a') & mi(`x')
~ Eric
__
Eric A. Booth
Public Policy Research Institute
Texas A&M University
[email protected]
Office: +979.845.6754
On Jul 8, 2010, at 10:41 AM, Eric Booth wrote:
> <>
>
> I think you just want:
>
> gen x = .
> foreach a in `range' {
> replace x = `a' if !mi(`a') & mi(`x')
> }
>
> Unless I am not understanding your description (if not, an example with some sample data would be useful)
>
> Also, note that your loop:
>
> scalar i=1
> foreach a in {range} {
> ...
> gen x={output} in i
> i++ //or i=i+1
> }
>
> would not work because you are asking Stata to re-generate "x" each time it passes through the loop.
>
> ~ Eric
>
> __
> Eric A. Booth
> Public Policy Research Institute
> Texas A&M University
> [email protected]
> Office: +979.845.6754
>
> On Jul 8, 2010, at 10:32 AM, Dani Tilley wrote:
>
>> Hi,
>>
>> I'm trying to store certain output in a new variable while I loop through
>> different categories. At the end I want to average what I've stored and perhaps
>> do some other manipulations. Right now, my code looks like this:
>>
>> foreach a in {range} {
>> ...
>> gen x`a'={output} in 1
>> ...
>> }
>>
>> su x*, mean
>> di r(mean)
>> drop x*
>>
>> So I create `a' variables that have the desired output as their 1st observations
>> and N-1 missing points. I then average across these variables and drop them.
>> While this gets the job done, I feel it's very clumsy. I'm looking to create a
>> single variable, x, that will hold all `a' outputs. Something like
>>
>> scalar i=1
>> foreach a in {range} {
>> ...
>> gen x={output} in i
>> i++ //or i=i+1
>> }
>>
>> Thanks,
>> DF Tilley
>>
>>
>>
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