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st: RE: Extract Year from String


From   "Martin Weiss" <[email protected]>
To   <[email protected]>
Subject   st: RE: Extract Year from String
Date   Tue, 13 Oct 2009 20:11:55 +0200

<>

**************
di  year(dofc(clock("Dec/17/1998 11:30:00 PM", "MDY hms")))
**************


HTH
Martin

-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of [email protected]
Sent: Dienstag, 13. Oktober 2009 20:06
To: [email protected]
Subject: st: Extract Year from String

I need to extract year from a string variable (str24  %24s).
How can I extract, for example, 1998 from this observation:
Dec/17/1998 11:30:00 PM
Thank you.

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