with -set race on- this is where it stops...
------------------------------------------------------------------
end _fr_area_parse_and_log ---
- _fr_area_parse_and_log `log' plotregion1 PLOTRegion , `r(rest)'
= _fr_area_parse_and_log __000001 plotregion1 PLOTRegion ,
l1title(`""') b1title(`"birth_month"') n
> ote("Graphs by dummy variable equal to one if urban, zero if rural)
----------------------------------------------------------------
begin _fr_area_parse_and_log ---
- gettoken log 0 : 0
- gettoken object 0 : 0
- gettoken parseopt 0 : 0
- local opt = lower("`parseopt'")
= local opt = lower("PLOTRegion")
- syntax [ , `parseopt'(string) * ]
= syntax [ , PLOTRegion(string) * ]
unmatched quote
------------------------------------------------------------------
end _fr_area_parse_and_log ---
----------------------------------------------------------------------
end bygraph_g.parse_make ---
- if (_rc == 4023) InvalidFamily `do'
= if (_rc == 4023) InvalidFamily twoway
- else if (_rc) exit _rc
}
if "`.`name'._scheme.isa'" != "" {
set curscm `.`name'._scheme.objkey'
}
}
---------------------------------------------------------------------------------
end graph.Graph ---
- local rc = _rc
- gdi record = yes
- gdi maybedraw = yes
- gdi end
- exit `rc'
= exit 198
-----------------------------------------------------------------------------------------
end graph ---
------------------------------------------------------------------------------------------
end twoway ---
r(198);
r(198);
On Mon, Mar 16, 2009 at 12:14 PM, Rike <[email protected]> wrote:
> Yes-
>
> ta status
> 0 rural
> 1 urban
>
> but I still can't get the graph work..
>
>
>
> On Mon, Mar 16, 2009 at 11:28 AM, Richard Ochmann <[email protected]> wrote:
>> does this do what you want?
>>
>> ***
>> label define status 0 "rural", modify
>> label values status status
>> tab status
>> ***
>>
>> assuming the variable "status" exists.
>>
>> best, rich
>>
>>
>>
>>
>> Rike <[email protected]>
>> Gesendet von: [email protected]
>> 16.03.2009 16:16
>> Bitte antworten an
>> [email protected]
>>
>>
>> An
>> [email protected]
>> Kopie
>>
>> Thema
>> Re: st: RE: twoway scatter returns "unmatched quote"
>>
>>
>>
>>
>>
>>
>> I added "modify"
>>
>> label define status 0 "rural", modify
>>
>> is what I did (sorry). But
>>
>> ta status
>>
>> returns
>>
>> 0
>>
>> 1 urban
>>
>>
>>
>>
>>
>> On Mon, Mar 16, 2009 at 11:10 AM, Friedrich Huebler <[email protected]>
>> wrote:
>>> Rike,
>>>
>>> What do you mean by "it doesn't add a label for 0"? Stata can assign
>>> labels to zeros. Did you forget the -modify- option?
>>>
>>> . sysuse auto
>>> . d foreign
>>> storage display value
>>> variable name type format label variable label
>>> ------------------------------------------------------------
>>> foreign byte %8.0g origin Car type
>>>
>>> . lab list origin
>>> origin:
>>> 0 Domestic
>>> 1 Foreign
>>>
>>> . lab def origin 0 "Rural", modify
>>> . lab list origin
>>> origin:
>>> 0 Rural
>>> 1 Foreign
>>>
>>> . tab foreign
>>> Car type | Freq. Percent Cum.
>>> ------------+-----------------------------------
>>> Rural | 52 70.27 70.27
>>> Foreign | 22 29.73 100.00
>>> ------------+-----------------------------------
>>> Total | 74 100.00
>>>
>>> Friedrich
>>>
>>> On Mon, Mar 16, 2009 at 10:54 AM, Rike <[email protected]> wrote:
>>>> Hi,
>>>>
>>>> I think the problem lies in the label. The variable "status"" takes 0
>>>> for rural and 1 for urban, but I'm not able to assign a label to 0
>>>> (and "urban" is already assigned to 1). I ran
>>>>
>>>> la def status 0 "rural"
>>>>
>>>> it doesn't add a label for 0 which is odd...
>>>>
>>>>
>>>> On Mon, Mar 16, 2009 at 7:21 AM, Nick Cox <[email protected]> wrote:
>>>>> No quotes are included in what you report here as typed.
>>>>>
>>>>> So, check out in turn
>>>>>
>>>>> 1. Any unmatched quotes in the variable label of -status-.
>>>>>
>>>>> 2. Any unmatched quotes in the value labels of -status- (if any).
>>>>>
>>>>> 3. Any unmatched quotes in the values of -status- (if it is a string
>>>>> variable).
>>>>>
>>>>> 4. Repeat 1 for your other variables.
>>>>>
>>>>> My guess is #1.
>>>>>
>>>>> Then remove the unmatched quote _or_ insert a matching quote and
>> reissue
>>>>> the -graph- command.
>>>>>
>>>>> Nick
>>>>> [email protected]
>>>>>
>>>>> Rike
>>>>>
>>>>> I tried it without the space (I mistakenly put it back there when I
>>>>> copied the code for the list) but I get the same error. Any other
>>>>> ideas?
>>>>>
>>>>> Kieran McCaul
>>>>>
>>>>>> You have a space in the -by- option.
>>>>>> -by (status)- should be -by(status)-
>>>>>
>>>>> Rike
>>>>>
>>>>>> I'm running the following code:
>>>>>>
>>>>>> twoway scatter ratio month, by(status) c(l) xlabel(1(1)12)
>>>>>>
>>>>>> twoway scatter ratio1 ratio2 ratio3 ratio4 month, by (status)
>>>>>> connect(l l l l) xlabel(1(1)12)
>>>>>>
>>>>>> where status is a dummy. Stata returns an r(198) error, and it
>>>>>> happened when I added the by-option. I would also like to use
>>>>>> by(status, total) later on. Any suggestions? Thanks in advance.
>>> *
>>> * For searches and help try:
>>> * http://www.stata.com/help.cgi?search
>>> * http://www.stata.com/support/statalist/faq
>>> * http://www.ats.ucla.edu/stat/stata/
>>>
>>
>> *
>> * For searches and help try:
>> * http://www.stata.com/help.cgi?search
>> * http://www.stata.com/support/statalist/faq
>> * http://www.ats.ucla.edu/stat/stata/
>>
>>
>> *
>> * For searches and help try:
>> * http://www.stata.com/help.cgi?search
>> * http://www.stata.com/support/statalist/faq
>> * http://www.ats.ucla.edu/stat/stata/
>>
>
*
* For searches and help try:
* http://www.stata.com/help.cgi?search
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
