Yes-
ta status
0 rural
1 urban
but I still can't get the graph work..
On Mon, Mar 16, 2009 at 11:28 AM, Richard Ochmann <[email protected]> wrote:
> does this do what you want?
>
> ***
> label define status 0 "rural", modify
> label values status status
> tab status
> ***
>
> assuming the variable "status" exists.
>
> best, rich
>
>
>
>
> Rike <[email protected]>
> Gesendet von: [email protected]
> 16.03.2009 16:16
> Bitte antworten an
> [email protected]
>
>
> An
> [email protected]
> Kopie
>
> Thema
> Re: st: RE: twoway scatter returns "unmatched quote"
>
>
>
>
>
>
> I added "modify"
>
> label define status 0 "rural", modify
>
> is what I did (sorry). But
>
> ta status
>
> returns
>
> 0
>
> 1 urban
>
>
>
>
>
> On Mon, Mar 16, 2009 at 11:10 AM, Friedrich Huebler <[email protected]>
> wrote:
>> Rike,
>>
>> What do you mean by "it doesn't add a label for 0"? Stata can assign
>> labels to zeros. Did you forget the -modify- option?
>>
>> . sysuse auto
>> . d foreign
>> storage display value
>> variable name type format label variable label
>> ------------------------------------------------------------
>> foreign byte %8.0g origin Car type
>>
>> . lab list origin
>> origin:
>> 0 Domestic
>> 1 Foreign
>>
>> . lab def origin 0 "Rural", modify
>> . lab list origin
>> origin:
>> 0 Rural
>> 1 Foreign
>>
>> . tab foreign
>> Car type | Freq. Percent Cum.
>> ------------+-----------------------------------
>> Rural | 52 70.27 70.27
>> Foreign | 22 29.73 100.00
>> ------------+-----------------------------------
>> Total | 74 100.00
>>
>> Friedrich
>>
>> On Mon, Mar 16, 2009 at 10:54 AM, Rike <[email protected]> wrote:
>>> Hi,
>>>
>>> I think the problem lies in the label. The variable "status"" takes 0
>>> for rural and 1 for urban, but I'm not able to assign a label to 0
>>> (and "urban" is already assigned to 1). I ran
>>>
>>> la def status 0 "rural"
>>>
>>> it doesn't add a label for 0 which is odd...
>>>
>>>
>>> On Mon, Mar 16, 2009 at 7:21 AM, Nick Cox <[email protected]> wrote:
>>>> No quotes are included in what you report here as typed.
>>>>
>>>> So, check out in turn
>>>>
>>>> 1. Any unmatched quotes in the variable label of -status-.
>>>>
>>>> 2. Any unmatched quotes in the value labels of -status- (if any).
>>>>
>>>> 3. Any unmatched quotes in the values of -status- (if it is a string
>>>> variable).
>>>>
>>>> 4. Repeat 1 for your other variables.
>>>>
>>>> My guess is #1.
>>>>
>>>> Then remove the unmatched quote _or_ insert a matching quote and
> reissue
>>>> the -graph- command.
>>>>
>>>> Nick
>>>> [email protected]
>>>>
>>>> Rike
>>>>
>>>> I tried it without the space (I mistakenly put it back there when I
>>>> copied the code for the list) but I get the same error. Any other
>>>> ideas?
>>>>
>>>> Kieran McCaul
>>>>
>>>>> You have a space in the -by- option.
>>>>> -by (status)- should be -by(status)-
>>>>
>>>> Rike
>>>>
>>>>> I'm running the following code:
>>>>>
>>>>> twoway scatter ratio month, by(status) c(l) xlabel(1(1)12)
>>>>>
>>>>> twoway scatter ratio1 ratio2 ratio3 ratio4 month, by (status)
>>>>> connect(l l l l) xlabel(1(1)12)
>>>>>
>>>>> where status is a dummy. Stata returns an r(198) error, and it
>>>>> happened when I added the by-option. I would also like to use
>>>>> by(status, total) later on. Any suggestions? Thanks in advance.
>> *
>> * For searches and help try:
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>> * http://www.ats.ucla.edu/stat/stata/
>>
>
> *
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>
>
> *
> * For searches and help try:
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> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
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* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
