thanks joseph
thats exactly what i need!
> -----Ursprüngliche Nachricht-----
> Von: "Joseph Coveney" <[email protected]>
> Gesendet: 22.02.09 05:07:35
> An: <[email protected]>
> Betreff: st: RE: replace loop over var w/ if
> John Bunge wrote:
>
> i have 3 variables called v1d, v2d, v3d which all equal to .
>
> moreover i have 3 variables a1, a2, a3 which equal to . or some numerical
> value
>
> i want
> replace v1d = 1 if a1 ~=.
> replace v2d = 1 if a2 ~=.
> replace v3d = 1 if a3 ~=.
>
> how can i do this in 1 command? with forvalue?
>
> ------------------------------------------------------------------------------
> --
>
> Not sure about a single line of code, but the following should work.
>
> forvalues i = 1/3 {
> replace v`i'd = 1 if !missing(a`i')
> }
>
> If you're using v?d variables as flags for nonmissing values in the
> corresponding a? variables, then be aware that v?d will always test True,
> because they'll be either . or 1, both of which are nonzero. If you're using
> v?d variables as nonmissing-value indicator variable for a?, then the
> following would be better.
>
> forvalues i = 1/3 {
> replace v`i'd = !missing(a`i')
> }
>
> In this case, v?d will be 1 (True) if a? is not missing, and 0 (False)
> otherwise.
>
> Joseph Coveney
>
>
>
> *
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>
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