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Re: st: additional lines in a plot
From
stef salvez <[email protected]>
To
[email protected]
Subject
Re: st: additional lines in a plot
Date
Sat, 9 Jun 2012 15:24:25 +0100
Thank you for this Nick,
I add to my initial code what you proposed; that is,
su Austria, meanonly
local max = r(max)
local date = r(min)
local dates `date'
while `date' < `max' {
local date = `date' + 28
local dates `dates' `date'
}
and works perfectly.
I only get a warning sign when I then type
scatter Aus dAustria, xline(`dates', lstyle(grid) lw(vvthin) lcolor(gs12))
invalid line argument, .
r(198);
Do I miss something?
On 6/9/12, Nick Cox <[email protected]> wrote:
> Various ways depending on your rule for which you want plotted.
>
> But here is one.
>
> su datevar, meanonly
>
> local max = r(max)
> local date = r(min)
> local dates `date'
>
> while `date' < `max' {
> local date = `date' + 28
> local dates `dates' `date'
> }
>
> ... xli(`dates', lstyle(grid) lw(vvthin) lcolor(gs12))
>
> But judging from your example data this will just make a busy graph
> busier. I would think in terms of plotting
>
> (time since last date) vs (this date)
>
> to make the gaps more evident.
>
> Nick
>
> On Fri, Jun 8, 2012 at 10:29 PM, stef salvez <[email protected]>
> wrote:
>> But I do not know how to add these vertical lines every 28 dates. Some
>> help would be greatly appreciated. It is an advanced topic and you are
>> the right person to provide some information
>>
>> On 6/8/12, stef salvez <[email protected]> wrote:
>>> Thanks Nick.
>>>
>>> As you said I added xline() for one time point for Austria:
>>>
>>>
>>> scatter Aus dAustria, xsize(20) ysize(8) c(l l) xline( 17922 ) ||///
>>> scatter Bel dBelgium , c(l l) || ///
>>> scatter Aus t10, ms(none) mla(dA2) mlabpos(910) || ///
>>> scatter Bel t9 , ms(none) mla(dB2) mlabpos(910) ///
>>> yla(9 "Belgium" 10 "Austria" , ang(h)) ///
>>> xla(`=mdy(10,5,2008)' `=mdy(1,1,2010)' `=mdy(1,1,2012)', format(%td))
>>> legend(off)
>>>
>>> and it worked. The only difficulty is that I have to insert manually
>>> all these numbers (like 17922) which are the numerical representation
>>> of the dates. IS there any quicker way to do that; as I have many
>>> countries and for each country I have a different a sequence of dates.
>>> One example would be sufficient for me to understand how to move on,
>>>
>>>
>>> thanks again
>>>
>>>
>>> On 6/8/12, Nick Cox <[email protected]> wrote:
>>>> -xaxis()- is an option, not a command, but of no help here. You want
>>>> -xline()-. See also the SJ Tip cited earlier today to you.
>>>>
>>>> Nick
>>>>
>>>> On Fri, Jun 8, 2012 at 6:30 PM, stef salvez <[email protected]>
>>>> wrote:
>>>>
>>>>> According to the dataset below i have observations every 28 days (4
>>>>> weeks) but in some cases i have jumps ( 35 days-or 5 weeks- and 42
>>>>> days -or 6 weeks).
>>>>>
>>>>> I would like to construct vertical gridlines every 28 days so as
>>>>> to see easier the one- and/or two-week shifts. The solution mignt be
>>>>> the
>>>>> -xaxis- command but i do not know exactly how to fit it to the code
>>>>> below
>>>>>
>>>>>
>>>>> clear all
>>>>> cd d:\
>>>>> input str8 (Austria Belgium )
>>>>> "2/11/08" "07/12/08"
>>>>> "30/11/08" "04/01/09"
>>>>> "28/12/08" "01/02/09"
>>>>> "25/01/09" "01/03/09"
>>>>> "22/02/09" "29/03/09"
>>>>> "22/03/09" "26/04/09"
>>>>> "19/04/09" "24/05/09"
>>>>> "17/05/09" "21/06/09"
>>>>> "14/06/09" "19/07/09"
>>>>> "12/07/09" "16/08/09"
>>>>> "09/08/09" "13/09/09"
>>>>> "06/09/09" "11/10/09"
>>>>> "04/10/09" "08/11/09"
>>>>> "01/11/09" "06/12/09"
>>>>> "29/11/09" "03/01/10"
>>>>> "27/12/09" "31/01/10"
>>>>> "31/01/10" "28/02/10"
>>>>> "28/02/10" "28/03/10"
>>>>> "28/03/10" "25/04/10"
>>>>> "25/04/10" "23/05/10"
>>>>> "23/05/10" "20/06/10"
>>>>> "20/06/10" "18/07/10"
>>>>> "18/07/10" "15/08/10"
>>>>> "15/08/10" "12/09/10"
>>>>> "12/09/10" "10/10/10"
>>>>> "10/10/10" "07/11/10"
>>>>> "07/11/10" "05/12/10"
>>>>> "05/12/10" "02/01/11"
>>>>> "01/01/11" "30/01/11"
>>>>> "30/01/11" "27/02/11"
>>>>> "27/02/11" "27/03/11"
>>>>> "27/03/11" "24/04/11"
>>>>> "24/04/11" "22/05/11"
>>>>> "22/05/11" "19/06/11"
>>>>> "19/06/11" "17/07/11"
>>>>> "17/07/11" "14/08/11"
>>>>> "14/08/11" "11/09/11"
>>>>> "11/09/11" "09/10/11"
>>>>> "09/10/11" "06/11/11"
>>>>>
>>>>> end
>>>>> gen dAustria = date(Austria, "DM20Y")
>>>>> gen dBelgium = date(Belgium, "DM20Y")
>>>>>
>>>>> gen dA2 = dAustria - dAustria[_n-1]
>>>>> gen dB2 = dBelgium - dBelgium[_n-1]
>>>>> gen Aus= 10
>>>>> gen Bel = 9
>>>>> gen t10 = (dAustria + dAustria[_n-1]) / 2
>>>>> gen t9 = (dBelgium + dBelgium[_n-1]) / 2
>>>>>
>>>>> scatter Aus dAustria, xsize(20) ysize(8) c(l l)|| scatter Bel
>>>>> dBelgium , c(l l) || //
>>>>> scatter Aus t10, ms(none) mla(dA2) mlabpos(910) || ///
>>>>> scatter Bel t9 , ms(none) mla(dB2) mlabpos(910)
>>>>> yla(9 "Belgium" 10 "Austria" , ang(h)) xla(, format(%td))
>>>>> legend(off)
>>>>>
>
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