Re: st: additional lines in a plot

[Nick Cox <njcoxstata@gmail.com>]

Various ways depending on your rule for which you want plotted.

But here is one.

su datevar, meanonly

local max = r(max)
local date = r(min)
local dates `date'

while `date' < `max' {
          local date = `date' + 28
          local dates `dates' `date'
}

... xli(`dates', lstyle(grid)  lw(vvthin) lcolor(gs12))

But judging from your example data this will just make a busy graph
busier. I would think in terms of plotting

(time since last date) vs (this date)

to make the gaps more evident.

Nick

On Fri, Jun 8, 2012 at 10:29 PM, stef salvez <loggyedy@googlemail.com> wrote:
> But I do not know how to add these vertical lines every 28 dates. Some
> help would be greatly appreciated. It is an advanced topic and you are
> the right person to provide some information
>
> On 6/8/12, stef salvez <loggyedy@googlemail.com> wrote:
>> Thanks Nick.
>>
>> As you said I added xline() for one time point for Austria:
>>
>>
>>   scatter Aus  dAustria, xsize(20) ysize(8) c(l l)  xline( 17922 ) ||///
>>  scatter Bel dBelgium , c(l l)    || ///
>>  scatter Aus t10, ms(none) mla(dA2) mlabpos(910) || ///
>>  scatter Bel t9 , ms(none) mla(dB2) mlabpos(910) ///
>>  yla(9 "Belgium"  10 "Austria"    , ang(h)) ///
>>  xla(`=mdy(10,5,2008)' `=mdy(1,1,2010)' `=mdy(1,1,2012)', format(%td))
>> legend(off)
>>
>> and it worked. The only difficulty is that I have to insert manually
>> all these numbers (like 17922) which are the numerical representation
>> of the dates. IS there any quicker way to do that; as I have many
>> countries and for each country I have a different a sequence of dates.
>> One example would be sufficient for me to understand how to move on,
>>
>>
>> thanks again
>>
>>
>> On 6/8/12, Nick Cox <njcoxstata@gmail.com> wrote:
>>> -xaxis()- is an option, not a command, but of no help here. You want
>>> -xline()-. See also the SJ Tip cited earlier today to you.
>>>
>>> Nick
>>>
>>> On Fri, Jun 8, 2012 at 6:30 PM, stef salvez <loggyedy@googlemail.com>
>>> wrote:
>>>
>>>>  According to the dataset below i have observations every 28 days (4
>>>> weeks)  but in some cases i have jumps ( 35 days-or 5 weeks- and 42
>>>> days -or 6 weeks).
>>>>
>>>>  I would like to construct vertical gridlines   every 28 days so as
>>>> to see easier the one- and/or two-week shifts. The solution mignt be
>>>> the
>>>>  -xaxis- command but i do not know exactly how to fit it to the code
>>>> below
>>>>
>>>>
>>>> clear all
>>>> cd d:\
>>>> input str8  (Austria           Belgium          )
>>>>  "2/11/08"     "07/12/08"
>>>> "30/11/08"          "04/01/09"
>>>> "28/12/08"          "01/02/09"
>>>> "25/01/09"          "01/03/09"
>>>> "22/02/09"          "29/03/09"
>>>> "22/03/09"          "26/04/09"
>>>> "19/04/09"          "24/05/09"
>>>> "17/05/09"          "21/06/09"
>>>> "14/06/09"          "19/07/09"
>>>> "12/07/09"          "16/08/09"
>>>> "09/08/09"          "13/09/09"
>>>> "06/09/09"          "11/10/09"
>>>> "04/10/09"          "08/11/09"
>>>> "01/11/09"          "06/12/09"
>>>> "29/11/09"          "03/01/10"
>>>> "27/12/09"          "31/01/10"
>>>> "31/01/10"          "28/02/10"
>>>> "28/02/10"          "28/03/10"
>>>> "28/03/10"          "25/04/10"
>>>> "25/04/10"          "23/05/10"
>>>> "23/05/10"          "20/06/10"
>>>> "20/06/10"          "18/07/10"
>>>> "18/07/10"          "15/08/10"
>>>> "15/08/10"          "12/09/10"
>>>> "12/09/10"          "10/10/10"
>>>> "10/10/10"          "07/11/10"
>>>> "07/11/10"          "05/12/10"
>>>> "05/12/10"          "02/01/11"
>>>> "01/01/11"          "30/01/11"
>>>> "30/01/11"          "27/02/11"
>>>> "27/02/11"          "27/03/11"
>>>> "27/03/11"          "24/04/11"
>>>> "24/04/11"          "22/05/11"
>>>> "22/05/11"          "19/06/11"
>>>> "19/06/11"          "17/07/11"
>>>> "17/07/11"          "14/08/11"
>>>> "14/08/11"          "11/09/11"
>>>> "11/09/11"          "09/10/11"
>>>> "09/10/11"          "06/11/11"
>>>>
>>>> end
>>>> gen dAustria = date(Austria, "DM20Y")
>>>> gen dBelgium = date(Belgium, "DM20Y")
>>>>
>>>> gen dA2 = dAustria - dAustria[_n-1]
>>>> gen dB2 = dBelgium - dBelgium[_n-1]
>>>>  gen Aus= 10
>>>> gen Bel = 9
>>>> gen t10 = (dAustria + dAustria[_n-1]) / 2
>>>> gen t9 = (dBelgium + dBelgium[_n-1]) / 2
>>>>
>>>>  scatter Aus  dAustria, xsize(20) ysize(8) c(l l)|| scatter Bel
>>>> dBelgium , c(l l)    || //
>>>> scatter Aus t10, ms(none) mla(dA2) mlabpos(910) || ///
>>>> scatter Bel t9 , ms(none) mla(dB2) mlabpos(910)
>>>>  yla(9 "Belgium"  10 "Austria"    , ang(h)) xla(, format(%td))
>>>> legend(off)
>>>>

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