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Re: st: calculating cumulative values of other observations
From
Eric Booth <[email protected]>
To
[email protected]
Subject
Re: st: calculating cumulative values of other observations
Date
Fri, 6 Apr 2012 20:29:36 -0500
<>
******************!
//input example data//
clear
inp ID str18 date str4 activity hours
1 20071230 A 10
1 20071122 A 11
2 20071120 A 5
3 20071210 B 6
3 20071111 B 24
3 20071130 F 20
3 20070511 B 49
4 20070611 A 50
end
//cleanup//
g date2 = date(date, "YMD")
format date2 %td
sort ID activity date2
//gen prior hours var//
g priorhrs = 0
forval n = 1/`=_N' {
by ID activity: replace priorhrs = ///
priorhrs + hours[_n-`n'] ///
if date2[_n]>=date2[_n-`n']
}
l
********************!
- Eric
__
Eric A. Booth
Public Policy Research Institute
Texas A&M University
[email protected]
+979.845.6754
On Apr 6, 2012, at 6:09 PM, KOTa wrote:
> Hi all,
>
> i have a data looking like this:
>
> ID date activity hours prior result should be:
> 1 20071230 A 10 ? <-- 11
> 1 20071122 A 11 ? 0
> 2 20071120 A 5 ? 0
> 3 20071210 B 6 ? 73
> 3 20071111 B 24 ? 49
> 3 20071130 F 20 ? 0
> 3 20070511 B 49 ? 0
> 4 20070611 A 50 ? 0
>
> (better picture here http://gyazo.com/5dc1218534d8b185ab22989069034b8a.png )
>
> i need to fill "prior" column with following:
> - amount of hours spent on same activity by same user(ID) prior to
> date of current activity.
>
> example:
> in case of observation 4(line 4) activity is B, so prior = sum of
> hours spent on activity B before it took place (i.e. before 20071210)
> there are 2 such observations, one with 49 hour, another with 24.
> Therefore, prior = 24+49=73.
>
>
> any suggestions how to make this simple?
>
> i was thinking to use "sort" and "by:", but i can't figure out how to
> conditionally("if") sum up values from different observations into
> "prior" var
> its not a first time i encounter similar problem and always took some
> way around, but this time i decided to ask, maybe there is proper,
> simple way to do this
>
> thank you in advance
>
> K.
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