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Re: st: question about defining a local
From
Phil Schumm <[email protected]>
To
[email protected]
Subject
Re: st: question about defining a local
Date
Sat, 12 Nov 2011 18:52:27 -0600
On Nov 12, 2011, at 5:08 PM, Daifeng He wrote:
> This is driving me nuts, but I just cannot see what's going wrong with my simple code. Basically, I am defining a local to do sample restriction so that I can quicky switch from one sample restriction to another in my regressions. Can anyboday tell me why my code below is wrong?
>
> . local state & st=="CA"
>
> . di "`state'"
> & st==CA"" invalid name
> r(198);
Your macro contains double quotes, so you need to enclose it in compound double quotes (see [U] 12.4 Strings):
. di `"`state'"'
& st=="CA"
Note that for what you're doing, you're better off creating an indicator variable, and then using that to restrict your sample (as opposed to trying to store part of a command string in a local macro). For example:
mark ca if state & st == "CA"
reg depvar [indepvars] if ca
The resulting code is more readable, and you're less likely to get bitten by something unexpected WRT macro expansion.
-- Phil
P.S. You may already be aware of this, but note that the statement
if state
will be true for any non-zero values of state (including missing).
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