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st: hshaz interpretation of the unobserved heterogeneity parameters
From
Judit VALL CASTELLO <[email protected]>
To
[email protected]
Subject
st: hshaz interpretation of the unobserved heterogeneity parameters
Date
Wed, 28 Sep 2011 12:05:38 +0200 (CEST)
Dear all,
I am fitting hshaz for the first time and I have problems with interpreting the coefficients and the unobserved heterogeneity parameters.
This is the output that I get fitting a model with flexible baseline hazard for each year (15 years) and ommiting one of the dummies instead of the constant term (only showing the estimation of the model with UH):
Iteration 0: log likelihood = -13360.79 (not concave)
Iteration 1: log likelihood = -13141.202 (not concave)
Iteration 2: log likelihood = -13135.162 (not concave)
Iteration 3: log likelihood = -13133.705 (not concave)
Iteration 4: log likelihood = -13132.713 (not concave)
Iteration 5: log likelihood = -13132.384
Iteration 6: log likelihood = -13131.923 (not concave)
Iteration 7: log likelihood = -13131.886
Iteration 8: log likelihood = -13131.497
Iteration 9: log likelihood = -13131.329
Iteration 10: log likelihood = -13131.238
Iteration 11: log likelihood = -13131.227
Iteration 12: log likelihood = -13131.227
Discrete time PH model, with discrete mixture Number of obs = 101139
LR chi2() = .
Log likelihood = -13131.227 Prob > chi2 = .
------------------------------------------------------------------------------
employment | Coef. Std. Err. z P>|z| [95% Conf. Interval]
-------------+----------------------------------------------------------------
hazard |
d2 | 2.202138 .0835986 26.34 0.000 2.038287 2.365988
d3 | 1.817322 .0942435 19.28 0.000 1.632608 2.002036
d4 | 1.559679 .1042669 14.96 0.000 1.35532 1.764039
d5 | 1.326683 .1144048 11.60 0.000 1.102453 1.550912
d6 | .9699759 .1286689 7.54 0.000 .7177896 1.222162
d7 | .9914302 .1361961 7.28 0.000 .7244907 1.25837
d8 | .5558144 .1620074 3.43 0.001 .2382858 .873343
d9 | .5627367 .1741448 3.23 0.001 .2214191 .9040543
d10 | .3581391 .2022719 1.77 0.077 -.0383066 .7545848
d11 | .3722488 .2234632 1.67 0.096 -.0657311 .8102287
d12 | .4746029 .2471491 1.92 0.055 -.0098004 .9590061
d13 | .3426948 .3125202 1.10 0.273 -.2698336 .9552232
d14 | -.5513795 .5904984 -0.93 0.350 -1.708735 .6059762
d15 | .3091984 .5912455 0.52 0.601 -.8496214 1.468018
fem | -.6304255 .0524701 -12.01 0.000 -.733265 -.5275859
agedisabil~y | -.0880126 .0030303 -29.04 0.000 -.0939519 -.0820732
totaldis | -3.095721 .2213199 -13.99 0.000 -3.5295 -2.661942
profcateg2 | .1461056 .0541343 2.70 0.007 .0400044 .2522068
profcateg3 | .1733369 .0991126 1.75 0.080 -.0209203 .3675941
lnbasereg | .2052545 .0567508 3.62 0.000 .094025 .3164839
pensln | -.3220117 .0415467 -7.75 0.000 -.4034417 -.2405816
selflj2 | -.0656422 .0537471 -1.22 0.222 -.1709846 .0397002
totempspe | .0086617 .0009305 9.31 0.000 .006838 .0104854
ur | -.033141 .0036001 -9.21 0.000 -.0401971 -.026085
_cons | 1.568922 .5036847 3.11 0.002 .5817179 2.556126
-------------+----------------------------------------------------------------
m2 |
_cons | .920075 .2086793 4.41 0.000 .511071 1.329079
-------------+----------------------------------------------------------------
logitp2 |
_cons | -.1763005 .8397107 -0.21 0.834 -1.822103 1.469502
-------------+----------------------------------------------------------------
Prob. Type 1 | .5439613 .2083048 2.61 0.009 .1870183 .8608183
Prob. Type 2 | .4560387 .2083048 2.19 0.029 .1391817 .8129817
------------------------------------------------------------------------------
Note: m1 = 0
The prob.Type 1 and 2 is the probability that someone in my sample belogs to the first (or second) type of individuals, but how should I interpret the m2 and the logitp2?
Also, how can I translate the coefficients (for example of the ur) into marginal effects or probabilities?
Thanks a lot for your help in advance!!!
Let me know if more information is required (as it is the first time that I am using the statalist).
Judit
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