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RE: st: RE: Generating a variable by assigning value form another variable
From
"Vassilopoulos Achilleas" <[email protected]>
To
<[email protected]>
Subject
RE: st: RE: Generating a variable by assigning value form another variable
Date
Wed, 13 Jul 2011 09:53:52 +0300
Dear Indu,
If main_owner is a string variable just add quotes to its value. Namely,
based on your last example:
id main_owner hrs hrs01 hrs02 hrs03 hrs04 hrs05 hrs06 hrs07 hrs08
hrs09 hrs10
1 01 . 20 10 . 5 .
. . . . .
2 01 . 30 . . 5 .
. . . . .
3 01 . 30 . . . .
. . . . .
4 02 . 25 40 10 . .
. . . . .
5 01 . 30 20 10 . .
. . . . .
With the following commands:
local xx "01 02 03 04 05 06 07 08 09 10"
foreach x of local xx {
replace hrs = hrs`x' if main_owner == "`x'"
}
Turns into:
id main_owner hrs hrs01 hrs02 hrs03 hrs04 hrs05 hrs06 hrs07 hrs08
hrs09 hrs10
1 01 20 20 10 . 5 .
. . . . .
2 01 30 30 . . 5 .
. . . . .
3 01 30 30 . . . .
. . . . .
4 02 40 25 40 10 . .
. . . . .
5 01 30 30 20 10 . .
. . . . .
which is probably what you want.
Hope this helps,
_____________ - _______________
Achilleas Vassilopoulos
Agricultural University of Athens,
Dept. of Agricultural Economics and Rural Development,
Lab. of Political Economy and European Integration.
Iera Odos 75, 11855, Athens, Greece
Tel: (+30) 210-5294726
Fax: (+30) 2105294786
e-mail : [email protected]
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Indu Khurana
Sent: Wednesday, July 13, 2011 3:05 AM
To: [email protected]
Subject: Re: st: RE: Generating a variable by assigning value form another
variable
Dear Achilleas,
Thanks for the help!!
But the above code did not work. It still generated all missing values.
I will re-frame and simplify my question: I have divided my data for
each single year.
I don't have any more year suffix( _2, _3....) attached with the variable.
gen hrs=.
local xx "01 02 03 04 05 06 07 08 09 10"
id main_owner hrs hrs01 hrs02 hrs03 hrs04........hrs10
1 01 . 20 10 . 5
2 01 . 30 . . 5
3 01 . 30 . . . .
4 02 . 25 40 10 .
5 01 . 30 20 10 .
.
.
5000 firms..............................................................
(main_owner is a string variable)
Now I want hrs to take value of hrs01 for id 1 ie hrs change from
"missing to 40"
and hrs to take value of hrs002 for id 4 ie hrs change from "missing to 20"
to look like:
id main_owner hrs hrs01 hrs02 hrs03 hrs04
1 01 20 20 10 . 5
2 01 30 30 . . 5
3 01 30 30 . . . .
4 02 40 25 40 10 .
5 01 30 30 20 10 ..
.
.
.
I will appreciate your comments.
Thanks!!
Regards
Indu
On Tue, Jul 12, 2011 at 1:42 AM, Vassilopoulos Achilleas
<[email protected]> wrote:
> The problem is within the loop; your notation is a bit sloppy there. This
> should work:
>
> local xx "01 02 03 04 05 06 07 08 09 10"
>
> foreach x of local xx {
> replace hours_2 = hours_`x'_2 if main_owner == `x'
> }
>
> Hope this helps,
> _____________ - _______________
>
> Achilleas Vassilopoulos
>
> Agricultural University of Athens,
> Dept. of Agricultural Economics and Rural Development,
> Lab. of Political Economy and European Integration.
> Iera Odos 75, 11855, Athens, Greece
>
> Tel: (+30) 210-5294726
> Fax: (+30) 2105294786
> e-mail : [email protected]
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of Indu Khurana
> Sent: Tuesday, July 12, 2011 7:52 AM
> To: [email protected]
> Subject: st: Generating a variable by assigning value form another
variable
>
> Dear Statalisters,
>
> Subject: Generating a variable by assigning value form another variable
>
> I have a panel data of 5000 firms. Each firm can have multiple owners,
> but in the first stage I identified the main owner using the first
> year data and kept it same for all 6 years.
> This was done through a -reshape- command. ( In the data, if main
> owner==1 means that the first person was the main owner.)
>
> Now I have something like:
> firm_id main owner age gender hours_1
> 1 1 30 M 20
> 2 2 20 F 30
> 3 1 30 F 35
> 4 1 40 M 20
> 5 1
> Basically this is the subset from year1 of the whole data.
>
> Now I want hours_worked each year to change because it is a time
> variant variable.
>
> When I merge this data with the rest of the data it looks like:
> firm_id main_owner age gendr hours_1 hours_01_2 hours_02_2
> hours_03_2.. hours_10_2..hours_10_6
> 1 1 30 M 20
> 2 2 20 F 30
> 3 1 30 F 35
> 4 1 40 M 20
> 5 1
>
> hours _01_2 means: hours worked by owner 1 in the second year.
> (hours_owner number* _ year)
> hours_02_2 means: hours worked by owner 2 in the second year.
>
> there are 1 to 10 owners and it goes over for 6 years.
>
> Now i generated 5 more variables hours_2 (for second year), hours_3,
> ....... hours_6
>
> I want hours_2 to take the value from the columns: hours_01_2
> hours_02_2 hours_03_2 ......... hours_10_2.
>
> If main owner identified in stage 1 is 1 then variable hours_2 should
> take the value from hours_01_2 and if
> If main owner identified in stage 1 is 2 then variable hours_2 should
> take the value from hours_02_2 .....and so on..
>
> I did:
> gen hours_2=.
> gen hours_3 =.
> ......
>
> local xx "01 02 03 04 05 06 07 08 09 10"
>
> for each x of local xx {
> replace hours_2 = hours_`x' if main_owner = " `x'"
> }
>
>
> But this does not work.
>
> Please guide.
>
> Thanks!!
> *
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