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Re: st: xtmixed with nonrtolerance. What happens?
From
Anders Alexandersson <[email protected]>
To
[email protected]
Subject
Re: st: xtmixed with nonrtolerance. What happens?
Date
Fri, 24 Jun 2011 08:54:45 -0400
I too would like to see the frequency distribution of your original
dependent variable (i.e., before standardization).
and, like Maarten, I would use xtmepoisson instead of xtmixed if the
outcome variable is a count.
Lukas, what is your sample population, e.g, the 40 or the 130 countries?
Why do you need completely balanced data (no missing values)?
Anders Alexandersson
[email protected]
Lukas wrote:
> 1) Concerning the missings, i took care to delete all data i don't have the complete time series for.
> This means that i had to drop from 130 countries over a 20 years period to 40 countries over a 15 years
> period. On the other hand, there are deffinitely no missing values.
On Fri, Jun 24, 2011 at 6:30 AM, Maarten Buis <[email protected]> wrote:
> --- On Fri, Jun 24, 2011 at 12:11 PM, "Lukas Bösch" wrote:
>> One more information:
>>
>> When i run the modell only with the complete export time series. Without any zeroes in the dependent data, the output looks like this:
> <snip>
>> sd(R.genus) | 2.93e-06 .0221629 0
>
> I would not trust that result. First, leaving out 0s means you select
> on your dependent variable, which is a very bad idea. Second, your
> results indicate that the genus variation is de facto 0 (2.93e-6 =
> 0.000000293), which given your context is very unlikely.
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