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st: RE: how to calculate cumulative number of organizations for stcox?
From
Nick Cox <[email protected]>
To
"'[email protected]'" <[email protected]>
Subject
st: RE: how to calculate cumulative number of organizations for stcox?
Date
Wed, 15 Jun 2011 22:55:03 +0100
Have a look at
FAQ . . . . . . . . . . . . . . Calculating the number of distinct values
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N. J. Cox
9/06 How do I calculate the number of distinct
values seen so far?
http://www.stata.com/support/faqs/data/distinctvalues.html
Nick
[email protected]
Caleb Southworth
My data include a continuous date and organizations. How can I
calculate the cumulative number of organizations in existence at time
t?
I could do this by year. My strategy at present it to calculate the
survival interval for h(t_i-t). I would like to calculate the number
of organizations in existence at the beginning of that interval.
Thanks!--Caleb
. stset date, id(id) fail(found==0)
id: id
failure event: found == 0
obs. time interval: (date[_n-1], date]
exit on or before: failure
------------------------------------------------------------------------------
621 total obs.
565 obs. end on or before enter()
------------------------------------------------------------------------------
56 obs. remaining, representing
56 subjects
18 failures in single failure-per-subject data
212648 total analysis time at risk, at risk from t = 0
earliest observed entry t = 0
last observed exit t = 8294
.
end of do-file
. stdes
failure _d: found == 0
analysis time _t: date
id: id
|-------------- per subject --------------|
Category total mean min median max
------------------------------------------------------------------------------
no. of subjects 56
no. of records 56 1 1 1 1
(first) entry time 0 0 0 0
(final) exit time 3797.286 1 3925 8294
subjects with gap 0
time on gap if gap 0 . . . .
time at risk 212648 3797.286 1 3925 8294
failures 18 .3214286 0 0 1
------------------------------------------------------------------------------
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