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RE: st: Formatting Dates
From
"Anna M. Pees" <[email protected]>
To
"[email protected]" <[email protected]>
Subject
RE: st: Formatting Dates
Date
Fri, 10 Jun 2011 14:48:18 +0000
One last question:
I tried looking this up but couldn't find information.
What if I want the "newage" in years and months? How could I do this?
~AMP
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Miller, Daniel P
Sent: Friday, June 10, 2011 9:17 AM
To: [email protected]
Subject: RE: st: Formatting Dates
Assuming that drawdate and birthdate are in a days format I am pretty certain that you can:
gen newage_p = Drawdate- birthdate
gen newage = mofd(newage_p)
drop newage_p
the Stata help file (type help dates_and_times) has a great deal of information on how to work with dates and to convert dates from one format to another
Daniel P. Miller, PhD
Assistant Professor
Human Behavior Department
Boston University School of Social Work
264 Bay State Road | Boston, MA 02215
617-353-3752 | 617-353-5612 (fax) | [email protected] P Please consider the environment before printing this e-mail.
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Oliver Jones
Sent: Friday, June 10, 2011 10:04 AM
To: [email protected]
Subject: Re: st: Formatting Dates
Sorry, maybe I didn't understand your question.
Now I assume it is no problem for you to create the variable containing the age in months, e.g. by typing
generate currentage_m = newage/30.4
And now you want to format it?
What exactly do mean by that?
Best
Oliver
Am 10.06.2011 15:14, schrieb Anna M. Pees:
> How would I do that? Sorry, so new to this.
> I can generate the new variable from the two dates but what do I use to format it?
>
> AMP
>
>
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of Oliver
> Jones
> Sent: Friday, June 10, 2011 8:10 AM
> To: [email protected]
> Subject: Re: st: Formatting Dates
>
> Hi,
>
> why don't you create a variable holding the age in months?
>
> Best
> Oliver
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