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Re: st: Generating a Variable
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: Generating a Variable
Date
Mon, 14 Feb 2011 01:21:08 +0000
This doesn't seem soluble with your example data. The only information
on who smokes concerns the mothers. Perhaps Goof wrote this mail.
However, there is an FAQ detailing technique in this territory.
FAQ . . Creating variables recording prop. of the other members of a group
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N. J. Cox
4/05 How do I create variables summarizing for each
individual properties of the other members of a
group?
http://www.stata.com/support/faqs/data/members.html
and this also may be useful:
FAQ . . Creating variables recording whether any or all possess some char.
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N. J. Cox
2/03 How do I create a variable recording whether any
members of a group (or all members of a group)
possess some characteristic?
http://www.stata.com/support/faqs/data/anyall.html
On Sun, Feb 13, 2011 at 5:23 PM, Don Ruby <[email protected]> wrote:
> Suppose I have the following data (excepting Ssmoke which I need to create):
>
> +--------------------------------------------------------+
> | Mid Sid Famid Msmoke Ssmoke |
> |----------------------------------------------------------|
> 1. | 1 2 1 0 1 |
> 2. | 2 1 1 1 0 |
> 3. | 3 4 2 1 0 |
> 4. | 4 3 2 0 1 |
> +--------------------------------------------------------+
>
> Where Mid is a mother id, Sid is a sibling id, and Famid is a family
> id. Msmoke indicates that the mother smoked.
>
> What is the simplest way to create a variable "Ssmoke" that equals 1
> if a sibling smoked, and 0 otherwise? (Note, there are families in
> which there are more than 2 siblings.)
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