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Re: st: Question about scalars
From
Austin Nichols <[email protected]>
To
[email protected]
Subject
Re: st: Question about scalars
Date
Mon, 9 Aug 2010 15:51:32 -0400
Steve et al.:
d is an abbrev for displacement, and the first obs is 121.
Use scalar(d) instead.
On Mon, Aug 9, 2010 at 3:26 PM, Jeph Herrin <[email protected]> wrote:
> Yes, but look closely at
>
>> . scalar e = d + a
>> . scalar dir a d e // "e" is wrong
>> a = 10
>> d = 4.9458042
>> e = 131
>
> You'll see that 4.94+10 = 131. Which is incorrect.
>
> cheers,
> Jeph
>
> On 8/9/2010 2:15 PM, Sergiy Radyakin wrote:
>>
>> Hi, Steve,
>>
>> there might be something else in your program that prevents it from
>> running. Both code fragments that you compare work fine in my Stata 9
>> and Stata 11.
>>
>> Best, Sergiy
>>
>> . do "R:\TEMP\STD0h000000.tmp"
>>
>> . clear
>>
>> . scalar drop _all
>>
>> . scalar a = 10
>>
>> . scalar b = 20
>>
>> . scalar c = b + a
>>
>> . scalar dir
>> c = 30
>> b = 20
>> a = 10
>>
>> .
>> . sysuse auto, clear
>> (1978 Automobile Data)
>>
>> . reg mpg foreign
>>
>> Source | SS df MS Number of obs =
>> 74
>> -------------+------------------------------ F( 1, 72) =
>> 13.18
>> Model | 378.153515 1 378.153515 Prob> F =
>> 0.0005
>> Residual | 2065.30594 72 28.6848048 R-squared =
>> 0.1548
>> -------------+------------------------------ Adj R-squared =
>> 0.1430
>> Total | 2443.45946 73 33.4720474 Root MSE =
>> 5.3558
>>
>>
>> ------------------------------------------------------------------------------
>> mpg | Coef. Std. Err. t P>|t| [95% Conf.
>> Interval]
>>
>> -------------+----------------------------------------------------------------
>> foreign | 4.945804 1.362162 3.63 0.001 2.230384
>> 7.661225
>> _cons | 19.82692 .7427186 26.70 0.000 18.34634
>> 21.30751
>>
>> ------------------------------------------------------------------------------
>>
>> . scalar d = _b[foreign]
>>
>> . scalar e = d + a
>>
>> . scalar dir a d e // "e" is wrong
>> a = 10
>> d = 4.9458042
>> e = 131
>>
>> .
>> . tempname dd
>>
>> . scalar `dd' = _b[foreign]
>>
>> . scalar e = `dd' +a
>>
>> . scalar dir a `dd' e // "e" is /okay
>> a = 10
>> __000000 = 4.9458042
>> e = 14.945804
>>
>> .
>> end of do-file
>>
>>
>> On Mon, Aug 9, 2010 at 1:57 PM, Steve Samuels<[email protected]> wrote:
>>>
>>> In the code below, I generate a scalar "d" from a regression result;
>>> it looks okay, but trying to add it to another scalar doesn't work.
>>> If, however I use a -tempname- , I get the right answer. Could
>>> someone explain to me why the first approach doesn't work and if
>>> there's another approach that doesn't involve a -tempname-?
>>>
>>> Thanks,
>>>
>>> Steve
>>>
>>> ******************************
>>> clear
>>> scalar drop _all
>>> scalar a = 10
>>> scalar b = 20
>>> scalar c = b + a
>>> scalar dir
>>>
>>> sysuse auto, clear
>>> reg mpg foreign
>>> scalar d = _b[foreign]
>>> scalar e = d + a
>>> scalar dir a d e // "e" is wrong
>>>
>>> tempname dd
>>> scalar `dd' = _b[foreign]
>>> scalar e = `dd' +a
>>> scalar dir a `dd' e // "e" is /okay
>>> ****************************
>>>
>>> --
>>> Steven Samuels
>>> [email protected]
>>> 18 Cantine's Island
>>> Saugerties NY 12477
>>> USA
>>> Voice: 845-246-0774
>>> Fax: 206-202-4783
>>>
>>> *
*
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