Re: st: Question about scalars

[Sergiy Radyakin <serjradyakin@gmail.com>]

Hi, Steve,

there might be something else in your program that prevents it from
running. Both code fragments that you compare work fine in my Stata 9
and Stata 11.

Best, Sergiy

. do "R:\TEMP\STD0h000000.tmp"

. clear

. scalar drop _all

. scalar a = 10

. scalar b = 20

. scalar c = b + a

. scalar dir
         c =         30
         b =         20
         a =         10

.
. sysuse auto, clear
(1978 Automobile Data)

. reg mpg foreign

      Source |       SS       df       MS              Number of obs =      74
-------------+------------------------------           F(  1,    72) =   13.18
       Model |  378.153515     1  378.153515           Prob > F      =  0.0005
    Residual |  2065.30594    72  28.6848048           R-squared     =  0.1548
-------------+------------------------------           Adj R-squared =  0.1430
       Total |  2443.45946    73  33.4720474           Root MSE      =  5.3558

------------------------------------------------------------------------------
         mpg |      Coef.   Std. Err.      t    P>|t|     [95% Conf. Interval]
-------------+----------------------------------------------------------------
     foreign |   4.945804   1.362162     3.63   0.001     2.230384    7.661225
       _cons |   19.82692   .7427186    26.70   0.000     18.34634    21.30751
------------------------------------------------------------------------------

. scalar d = _b[foreign]

. scalar e = d + a

. scalar dir a d e // "e" is wrong
         a =         10
         d =  4.9458042
         e =        131

.
. tempname dd

. scalar `dd' = _b[foreign]

. scalar e = `dd' +a

. scalar dir a `dd' e // "e" is /okay
         a =         10
  __000000 =  4.9458042
         e =  14.945804

.
end of do-file


On Mon, Aug 9, 2010 at 1:57 PM, Steve Samuels <sjsamuels@gmail.com> wrote:
> In the code below, I generate a scalar "d" from a regression result;
> it looks okay, but trying to add it to another scalar doesn't work.
> If, however I use a -tempname- , I get the right answer.  Could
> someone explain to me why the first approach doesn't work and if
> there's another approach that doesn't involve a -tempname-?
>
> Thanks,
>
> Steve
>
> ******************************
> clear
> scalar drop _all
> scalar a = 10
> scalar b = 20
> scalar c = b + a
> scalar dir
>
> sysuse auto, clear
> reg mpg foreign
> scalar d = _b[foreign]
> scalar e = d + a
> scalar dir a d e // "e" is wrong
>
> tempname dd
> scalar `dd' = _b[foreign]
> scalar e = `dd' +a
> scalar dir a `dd' e // "e" is /okay
> ****************************
>
> --
> Steven Samuels
> sjsamuels@gmail.com
> 18 Cantine's Island
> Saugerties NY 12477
> USA
> Voice: 845-246-0774
> Fax:    206-202-4783
>
> *
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>

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