Try this:
g mydate=date(date, "MDY") /* Second "date" is the 'original date
variable'.
format mydate %td
g dm=mofd(mydate)
format dm %tm
drop mydate
Hope it works.
Best,
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Ariel Linden,
DrPH
Sent: Wednesday, August 26, 2009 11:37 PM
To: [email protected]
Subject: st: extracting month and year from a date variable
Hi Fellow Stata Listservers,
I am trying to generate a variable that contains only the month and year,
extracted from another complete date variable. The ultimate intent is to
aggregate a given outcome by the month/year.
So for example, the original date value is 17374, which is displayed as
07/27/2007. I would like to generate a variable that is "Jul 2007" or
"07_2007" (I am not picky on the style, this is just to allow me to
aggregrate by this variable).
I get the feeling that I will have to convert this to a string and then
generate the variable with a substr statement, but I hope there is an easier
way.
Thanks in advance
Ariel
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