...
There are -year()-, -month()-, and -day()- functions that can extract
these components from a date variable.
See -help dates-
______________________________________________
Kieran McCaul MPH PhD
WA Centre for Health & Ageing (M573)
University of Western Australia
Level 6, Ainslie House
48 Murray St
Perth 6000
Phone: (08) 9224-2701
Fax: (08) 9224 8009
email: [email protected]
http://myprofile.cos.com/mccaul
http://www.researcherid.com/rid/B-8751-2008
______________________________________________
If you live to be one hundred, you've got it made.
Very few people die past that age - George Burns
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Ariel Linden,
DrPH
Sent: Thursday, 27 August 2009 11:37 AM
To: [email protected]
Subject: st: extracting month and year from a date variable
Hi Fellow Stata Listservers,
I am trying to generate a variable that contains only the month and
year,
extracted from another complete date variable. The ultimate intent is to
aggregate a given outcome by the month/year.
So for example, the original date value is 17374, which is displayed as
07/27/2007. I would like to generate a variable that is "Jul 2007" or
"07_2007" (I am not picky on the style, this is just to allow me to
aggregrate by this variable).
I get the feeling that I will have to convert this to a string and then
generate the variable with a substr statement, but I hope there is an
easier
way.
Thanks in advance
Ariel
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