Re: st: Macro from scalar

[Nick Winter <nwinter@virginia.edu>]

Note the difference between:

scalar s = 1
local l s

and

scalar s = 1
local l = s

in the first case, the string "s" is put in local l.  When you display 
`l', Stata replaces `l' with the string "s", which is then evaluated as 
a scalar.

In the second case, the local l is given the (current) value of the 
scalar s.

Which you want depends on whether you want the value you get when you 
refer to the local to change when the scalar changes.  Consider:

. scalar s = 1

. local m1 s

. local m2 = s

. scalar s = 2

. di `m1'
2

. di `m2'
1


--Nick Winter



Eva Poen wrote:

> Douglas,
>
> like this?
>
> scalar s = 1
> local l s
>
> di s
> di `l'
>
> To avoid confusion with variable names, you can write
>
> local l scalar(s)
>
> Hope this helps,
> Eva
>
>
> 2008/8/22 Levy, Douglas E., Ph.D. <DLEVY3@partners.org>:
> > Hi all,
> > Is there a way to take a scalar and place its value in a macro?
> > Thanks,
> > Doug
> >
> > Douglas Levy, PhD
> > Institute for Health Policy
> > Massachusetts General Hospital
> > 50 Staniford Street; Suite 901
> > Boston, MA 02114
> > Tel 617.643.3595
> > Fax 617.724.4738
> *
> *   For searches and help try:
> *   http://www.stata.com/help.cgi?search
> *   http://www.stata.com/support/statalist/faq
> *   http://www.ats.ucla.edu/stat/stata/
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--------------------------------------------------------------
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Assistant Professor                             434.924.3359 f
Department of Politics                  nwinter@virginia.edu e
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