Michael McCulloch wrote:
In the following simulated data, I'd like to create a table of mean age (row header) for:
each of 3 income levels (with income level the column sub-header)
within each of 2 groups (with group the column main header)
So that:
from left to right in the data area would groups 1, 2, and 3,
within each group, from left to right would be income categories
And in each cell the mean age.
Here are the data I've created:
clear
set obs 100
set seed 12358
gen age =30 + int(20*uniform())
format age %2.0f
gen income =1 + int(3*uniform())
gen group =1 + int(2*uniform())
==========================================================
It seems that you want a table with one row. The -table-
command interprets the first variable as the row variable,
so generating a variable with one value will do the trick.
That variable may even be a string variable:
generate str meanage = "Mean age"
table meanage group income , contents(mean age)
Hope this helps
Svend
________________________________________________________
Svend Juul
Institut for Folkesundhed, Afdeling for Epidemiologi
(Institute of Public Health, Department of Epidemiology)
Vennelyst Boulevard 6
DK-8000 Aarhus C, Denmark
Phone, work: +45 8942 6090
Phone, home: +45 8693 7796
Fax: +45 8613 1580
E-mail: [email protected]
_________________________________________________________
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