The problem is that `i' is being evaluated in the first line and becomes a blank.
The correct form is:
forvalues i = 1/6 {
.
.
.
-----------------------------------
Thomas J. Steichen
[email protected]
-----------------------------------
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Solorzano, Jenniffer
Sent: Wednesday, June 18, 2008 4:57 PM
To: [email protected]
Subject: st: I can't run a simple program!
Hi,
I don't know what is happening with my stata version. I'm trying to run
this simple program....
. program count6
1. forvalues `i'=1/6 {
2. display `i'
3. }
4. end
. count6
_= invalid name
r(198);
And that error appears from nothing, somebody can help me?
Thanks
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Man Jia
Sent: Wednesday, June 18, 2008 4:55 PM
To: [email protected]
Subject: st:Re: variables named T099`j'
Hi Mr. John-Paul Ferguson,
Thanks for your help! It works well. I did exactly as you suggested.
Thanks!
Mandy
John-Paul Ferguson wrote:
>Dear Mandy,
>
>I think that trying to manipulate j within the "if" statement on your
fourth
>line is causing the problem. If you first create another local macro
that's
>equal to that value and include it, the loop should work correctly. See
below:
>
>local j 0802
>forvalue i=1/8 {
> g age`i'=2006-T099`j'
> local k = `j'-1
> replace age`i'=2006-T099`j'-1 if T099`k' > 5
> local j = `j' + 500
>}
>
>I am assuming that the first "T099`j'-1" in the "replace" line is
>supposed to be the value of T099`j' minus 1, not the value of T099`k'
>as defined here.
Adjust
>accordingly.
>
>Best,
>
>John-Paul Ferguson
>MIT
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