Danielle--
I'm sure there's a more elegant solution, but
something like this might be easy:
. matrix T= (1,2,3,4\5,6,7,8)
. di T[2,3]
7
/*oops, I wanted the column third from last,
not the third column */
. di T[2,colsof(T)-2]
6
On 8/2/06, dferry <[email protected]> wrote:
The problem is that the results of dfgls for each lag are listed in reverse order (i.e., results for lag m are listed first and results for lag 1 are listed last). So, the line "local T = r[`optlag', 5]" does not grab the right row. Can I flip the matrix r around so (or re-sort the rows) so that the first row corresponds to the results for lag 1 and the row m corresponds to results for lag m? Or is there perhaps a better way to approach this?
Thanks,
Danielle
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