In addition
replace ID
needs to be followed immediately by an equals sign.
In your case, your criterion seems to be that
the first three characters are "fill". If so,
the whole apparatus of wildcards, matching,
regular expressions and what have you can be
avoided by using -substr()-.
gen id2 = id
replace id2 = "filled" if substr(id,1,3) == "fill"
or even
gen id2 = cond(substr(id,1,3) == "fill", "filled", id)
Nick
[email protected]
Fred Wolfe
> See this function from Stata help
>
> strmatch(s1,s2) evaluates to 1 if s1 matches the pattern
> s2; otherwise,
> it returns 0.
Joanna
> The new dataset contains the variable 'id' which
> contains string values "fill1", "fill 2" etc and "study 1",
> "study 2" etc. I have tried the following commands:
>
> gen id2=id
> replace id2 "filled" if id=="fill*"
>
> which didn't work. I cannot find any reference of a
> wildcard being used
> in such a situation, is it possible? I'm sure there is a
> very simple
> solution to my problem so I apologise in advance!
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