Sorry for the confused question... it is the result of a confused
mind. I have many thousands of observations (zip codes and telephone
exchanges to be precise) and there are a lot more groups than 2 (in my
example there was one unique combo and everything else being groups).
I don't know how many "legs" the biggest group has but will look at
Michael's code to see if I can get it to work.
Thanks Scott and Mikael for your responses!
Fredrik
On 7/29/05, Scott Merryman <[email protected]> wrote:
> I didn't think it was so simple, but I did not find the question very clear.
> Are the linked observations defined when zdup and edup are greater than zero
> or on some other criteria? Do the linked observations comprise one group
> and the unlinked observations a second group? Or does each of the unlinked
> observation comprise a separate group?....Anyway, I think your
> interpretation is correct and I am glad you had a solution.
>
> Scott
>
>
> > -----Original Message-----
> > From: [email protected] [mailto:owner-
> > [email protected]] On Behalf Of Michael Blasnik
> > Sent: Friday, July 29, 2005 6:52 PM
> > To: [email protected]
> > Subject: st: Re: RE: Finding and tagging overlapping groups
> >
> > I don't believe this response answers the (admittedly somewhat confusing)
> > request at all, it just happens to work for the sample observations given.
> > It only works if one observation is completely unique on the 2 vars and
> > all
> > others form one group with overlap. I think the post was looking for a
> > way
> > of classifying cases into groups (most likely more than 2) if they match
> > on
> > either of two variables anywhere in the dataset.
> >
> > Michael Blasnik
> > [email protected]
> >
> > ----- Original Message -----
> > From: "Scott Merryman" <[email protected]>
> > To: <[email protected]>
> > Sent: Friday, July 29, 2005 7:41 PM
> > Subject: st: RE: Finding and tagging overlapping groups
> >
> >
> > > gen group = cond(zd>0 | ed>0, 1, 2)
> > >
> > > Scott
> >
> >
> > *
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> > * http://www.ats.ucla.edu/stat/stata/
>
>
> *
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