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Re: st: graphing median values against time
From
Donald Spady <[email protected]>
To
Statalist Statalist <[email protected]>
Subject
Re: st: graphing median values against time
Date
Wed, 9 Apr 2014 08:58:09 -0600
I dont think that is the case. I used a Regex search in two different text editors to look for non-ASCII characters and came up with nothing. Besides, if there was a non-ascii char, would it not show up in the other commands, where I had not added the lcolor(black) bit. I have run it many times without that option and no problems.
Don
On Apr 9, 2014, at 8:06 AM, Nick Cox <[email protected]> wrote:
> I'd check for strange characters. Copy your command line into a string
> variable and look for unusual ASCII characters with -charlist- (SSC)
> or any alternative of your choice.
> Nick
> [email protected]
>
>
> On 9 April 2014 14:25, Donald Spady <[email protected]> wrote:
>> Tim
>> After digesting your and Nick's advice I have used the lgraph command to good effect; however I have one problem. If I write:
>> foreach name in "cumten" "cumswol" {
>> igraph `name' following if visspell !=. & recnum == 1, by(aborig) label(0 3 9 15, lab size(tiny)) stat(mean) title("Mean `name' (Median:nonFN:Navy; FN:Gold)",size(small)) label(#10) also collapse((median) median = `name') addplot(line median following if aborig == 0, lcolor(dknavy) clwidth(thick)|| line median following if aborig == 1)
>> }
>>
>> everything works fine and I get pretty pictures.
>>
>> BUT if I write:
>> foreach name in "cumten" "cumswol" {
>> lgraph `name' following if visspell !=. & recnum == 1, by(aborig) label(0 3 9 15, lab size(tiny)) stat(mean) title("Mean `name' (Median:nonFN:Navy; FN:Gold)",size(small)) label(#10) also collapse((median) median = `name') addplot(line median following if aborig == 0, lcolor(dknavy) clwidth(thick)|| line median following if aborig == 1, lcolor(black))
>> }
>> The only change is the addition of lcolor(black) at the end of the command.
>>
>> I get the message:
>> invalid 'title'
>> r(198)
>>
>> Why. And how do I fix it.
>>
>> Many thanks.
>> Don
>>
>> On Mar 30, 2014, at 8:43 PM, Timothy Mak <[email protected]> wrote:
>>
>>> <>
>>> Thanks Nick very much for helping to answer my question.
>>>
>>> To plot more than one summary statistics is a bit difficult, and you do have to use the -addplot- and the -alsocollapse- options. If you hadn't specified -by(aborig)-, then Nick's syntax would be almost right, except that you don't need the -if bvisittm1N- in the end, i.e. -addplot(line median bvisittm1N)- would do. However, because you have specified -by(aborig)-, you really need to do:
>>>
>>> addplot(line median bvisittm1N if aborig == 1 || line median bvisittm1N if aborig == 2)
>>>
>>> supposing your variable aborig has 2 levels (1,2).
>>>
>>> To understand the use of the -addplot- and the -alsocollapse- option a bit more, you may want to use the -nopreserve- option. This gives you the dataset that -lgraph- actually uses to plot your graph. Also, have a look at the macros `r(command)' and `r(options)'. This gives you the -twoway- syntax that lgraph uses on the collapsed data. Be sure to use command double quotes though when you display the macros, i.e.:
>>>
>>> di `"`r(command)'"'
>>> di `"`r(options)'"'
>>>
>>> I hope that helps.
>>>
>>> Tim
>>>
>>>
>>> -----Original Message-----
>>> From: [email protected] [mailto:[email protected]] On Behalf Of Nick Cox
>>> Sent: 31 March 2014 08:38
>>> To: [email protected]
>>> Subject: Re: st: graphing median values against time
>>>
>>> You *must* specify a -twoway- subcommand, not -lgraph-, in the
>>> -addplot()- call. This is documented in the help for -addplot option-.
>>>
>>> I doubt very much that giving the same variable names as in the main
>>> call will do what you want.
>>>
>>> My second guess is that you need something more like
>>>
>>> alsocollapse((median) median=totend28)
>>> addplot(line median bvisittm1N if bvisittm1N)
>>>
>>> Nick
>>> [email protected]
>>>
>>>
>>> On 31 March 2014 01:29, Donald Spady <[email protected]> wrote:
>>>> Nick
>>>> I had tried various combinations of that command and could not get it to work.
>>>>
>>>> here is my command
>>>> .lgraph tottend28 bvisittm1N if bvisittm1N < 55, by(aborig) xlabel(0(3)54) stat(mean) alsocollapse((median)) addplot(lgraph tottend28 bvisittm1N if bvisittm1N <55, by(aborig))
>>>>
>>>> It doesn't work. I get the error
>>>> lgraph is not a twoway plot type
>>>> r(198);
>>>>
>>>> Don
>>>> On Mar 30, 2014, at 5:14 PM, Nick Cox <[email protected]> wrote:
>>>>
>>>>> Timothy explains how to do that in the help.
>>>>>
>>>>> addplot(plot) This allows additional twoway plots to be plotted.
>>>>> See addplot_option. Note that
>>>>> because lgraph collapses the data before plotting in twoway,
>>>>> plots given in addplot(plot)
>>>>> should also refer to the collapsed data. Specify in
>>>>> alsocollapse(clist) any additional data
>>>>> that need to be collapsed.
>>>>>
>>>>> So, if you want median as well as mean you must specify
>>>>>
>>>>> alsocollapse(median) addplot(<whatever>)
>>>>>
>>>>> Note that nothing obliges you to use another -line- call.
>>>>>
>>>>> I haven't use -lgraph-, just looked at its help, but Timothy provides
>>>>> lots of functionality.
>>>>> Nick
>>>>> [email protected]
>>>>>
>>>>>
>>>>> On 30 March 2014 23:51, Donald Spady <[email protected]> wrote:
>>>>>> Timothy
>>>>>> I am using your -lgraph- command and wonder if it is possible to have TWO stats created (e.g. mean and median) for the same variable(s) at the same time. I want to plot both mean and median and cannot create an overlay to do so.
>>>>>>
>>>>>> Many thanks
>>>>>> Don
>>>>>> On Mar 28, 2014, at 1:29 AM, Timothy Mak <[email protected]> wrote:
>>>>>>
>>>>>>> The command -lgraph- that I wrote is for exactly this kind of problem if you don't want to create all the variables before plotting a graph.
>>>>>>> You can see it by typing:
>>>>>>> ssc des lgraph
>>>>>>>
>>>>>>> Tim
>>>>>>>
>>>>>>> -----Original Message-----
>>>>>>> From: [email protected] [mailto:[email protected]] On Behalf Of Donald Spady
>>>>>>> Sent: 28 March 2014 08:59
>>>>>>> To: Statalist Statalist
>>>>>>> Subject: Re: st: graphing median values against time
>>>>>>>
>>>>>>> Nick
>>>>>>> It works. Just as I needed. Many thanks.
>>>>>>> John: That suggestion didn't work the way I wanted it to, but thanks for the idea.
>>>>>>>
>>>>>>> Don
>>>>>>> On Mar 27, 2014, at 5:48 PM, Nick Cox <[email protected]> wrote:
>>>>>>>
>>>>>>>> Sure. If you use -egen-'s -median()- and -mean()- functions to get the
>>>>>>>> variables you want, then it's any graph you want.
>>>>>>>>
>>>>>>>> As the median and mean values are repeated, don't plot them repeatedly.
>>>>>>>>
>>>>>>>> Here are some dopey examples.
>>>>>>>>
>>>>>>>> . webuse grunfeld
>>>>>>>>
>>>>>>>> . egen median = median(invest), by(year)
>>>>>>>>
>>>>>>>> . egen mean = mean(invest), by(year)
>>>>>>>>
>>>>>>>> . egen tag = tag(year)
>>>>>>>>
>>>>>>>> . line mean median year if tag
>>>>>>>>
>>>>>>>> For finer subdivisions, just use more variables as arguments to -by()-.
>>>>>>>>
>>>>>>>> Nick
>>>>>>>> [email protected]
>>>>>>>>
>>>>>>>>
>>>>>>>> On 27 March 2014 22:34, Donald Spady <[email protected]> wrote:
>>>>>>>>> Dear all
>>>>>>>>> I want to graph the median and mean values of a series of variables against a time variable (on the X axis) and with the option of stratifying the variables by another one (such as sex or disease state). I think I can do this by collapsing the data but is it possible to do this while retaining the data set in its 'original' state. I have searched the archives and the reference manuals but have not come up with anything that seems to be what I want.
>>>>>>>>> In many ways what I would like is a box plot with JUST the median (or mean) being plotted: no box, no outliers. Is that possible.
>>>>>>>>>
>>>>>>>>> Thanks
>>>>>>>>> Don
>>>>>>>>> *
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>>>>>>>
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>>>>>>
>>>>>>
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>>>>
>>>>
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>>>
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>>
>>
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>
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