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RE: st: RE: Fitting distributions to right-sensored survival data


From   "Kabaso M.E." <[email protected]>
To   "[email protected]" <[email protected]>
Subject   RE: st: RE: Fitting distributions to right-sensored survival data
Date   Fri, 24 Jan 2014 14:46:06 +0000

Dear Statalist,

As below, I can get the scale parameter p from the output. I am stuck with the scale parameter for the distribution (Weibull in this case) which  I fit my data to

See the output below and kindly help

Thanks
Mushota


. streg, dist(weibull) time

         failure _d:  Censorship == 1
   analysis time _t:  (Last_StatusDate-origin)
             origin:  time ARV_start
                 id:  patientIdInt

Fitting constant-only model:

Iteration 0:   log likelihood = -30480.164
Iteration 1:   log likelihood =  -30394.76
Iteration 2:   log likelihood = -30394.576
Iteration 3:   log likelihood = -30394.576

Fitting full model:
Iteration 0:   log likelihood = -30394.576  

Weibull regression -- accelerated failure-time form 

No. of subjects =       183547                     Number of obs   =    183547
No. of failures =         5582
Time at risk    =    157273351
                                                   LR chi2(0)      =      0.00
Log likelihood  =   -30394.576                     Prob > chi2     =         .

------------------------------------------------------------------------------
          _t |      Coef.   Std. Err.      z    P>|z|     [95% Conf. Interval]
-------------+----------------------------------------------------------------
       _cons |   10.76499   .0470595   228.75   0.000     10.67276    10.85723
-------------+----------------------------------------------------------------
       /ln_p |  -.1471334   .0116291   -12.65   0.000     -.169926   -.1243409
-------------+----------------------------------------------------------------
           p |   .8631788    .010038                      .8437273    .8830787
         1/p |   1.158509   .0134724                      1.132402    1.185217
------------------------------------------------------------------------------

-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Kabaso M.E.
Sent: 26 November 2013 15:43
To: [email protected]
Subject: RE: st: RE: Fitting distributions to right-sensored survival data

Dear Maarten,
Thanks for your guidance.
I am able to obtain the shape parameter this way, what about the scale parameter?
Mushota

-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Maarten Buis
Sent: 22 November 2013 13:08
To: [email protected]
Subject: Re: st: RE: Fitting distributions to right-sensored survival data

On Fri, Nov 22, 2013 at 1:44 PM, Kabaso M.E. wrote:
> Essentially, I can use the streg for example to fit a Weibull model to my survival data but how can I get the model's parameters for me to recreate the pdf here fitted elsewhere?

The (transformed) parameters are returned in the matrix e(b). You can also use the -[]_b[]- syntax to get at specific parameters, see: -help _variables-. Here is an example:

*------------------ begin example ------------------ sysuse cancer streg i.drug age, dist(weibull) nohr matlist e(b)
di "p = "     exp([ln_p]_b[_cons])
di "1/p = " 1/exp([ln_p]_b[_cons])
*------------------- end example -------------------
* (For more on examples I sent to the Statalist see:
* http://www.maartenbuis.nl/example_faq )

Hope this helps,
Maarten

---------------------------------
Maarten L. Buis
WZB
Reichpietschufer 50
10785 Berlin
Germany

http://www.maartenbuis.nl
---------------------------------
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