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Re: st: combining two variables into one with matching type
From
Nick Cox <[email protected]>
To
"[email protected]" <[email protected]>
Subject
Re: st: combining two variables into one with matching type
Date
Sun, 8 Dec 2013 18:38:51 +0000
They have the same format, but that's not the issue.
As -zipfinal- is string, its values can never be equal to system
missing . which is a numeric value.
If you want to refer to missing values of -zipfinal-, they have value
"" or return 1 (true) to -missing(zipfinal)-.
(Your code doesn't give a clear idea of what you want to do, but I
focused on your question.)
Nick
[email protected]
On 8 December 2013 18:32, Shawn DuBravac <[email protected]> wrote:
> Trying to combine two variables into 1, but getting "type mismatch" despite the fact both variables have the same format
>
> . gen str5 zipcode1 = string(zipcode,"%05.0f")
> . destring zip, generate(zip1)
> zip has all characters numeric; zip1 generated as long
> (32340 missing values generated)
>
> . gen str5 z1 = string(zip1,"%05.0f")
>
> .
> . gen zipfinal= z1
>
> . replace zipfinal=zipcode1 if zipfinal==.
> type mismatch
> r(109);
>
> end of do-file
> r(109);
>
> . do "C:\Users\SDUBRA~1.CE\AppData\Local\Temp\STD01000000.tmp"
>
> . describe zipcode1 z1 zipfinal
>
> storage display value
> variable name type format label variable label
> -------------------------------------------------------------------------------
> zipcode1 str5 %9s
> z1 str5 %9s
> zipfinal str5 %9s
>
> .
> end of do-file
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