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Re: st: calculate maximum density of normal distribuion
From
Nick Bornschein <[email protected]>
To
[email protected]
Subject
Re: st: calculate maximum density of normal distribuion
Date
Fri, 22 Nov 2013 16:28:31 +0100
Here is the code I'm using, change mean and sd at the beginning and look
at the graph, the density is not the same:
clear
set obs 10000
set seed 2211
global mean = 5
global sd = 3
gen normal1 = rnormal($mean, $sd)
qui: su normal1
global min = r(min)
global min = round($min,.01)
display $min
qui: su normal1
global max = r(max)
global max = round($max,.01)
display $max
_pctile normal1, p(2.5)
global n1_1 = r(r1)
global n1_1 = round($n1_1,.01)
display $n1_1
_pctile normal1, p(97.5)
global n1_2 = r(r1)
global n1_2 = round($n1_2,.01)
display $n1_2
twoway function y=normalden(x,$mean,$sd), range($min $max) color(r) ||
///
function y=normalden(x,$mean,$sd), range($min $n1_1) recast(area)
color(dknavy) || ///
function y=normalden(x,$mean,$sd), range($n1_2 $max)
recast(area) color(dknavy) ///
xtitle("{it: {&mu}}")
///
xline($mean)
///
ytitle("") title("Normalverteilung")
///
subtitle("{&mu}=$mean {&sigma}=$sd mit {&alpha}=.05, 2-seitig")
///
legend(off) xlabel($n1_1 $mean $n1_2)
Am 22.11.13 16:12, schrieb Nick Cox:
That density is a constant, namely
. di normalden(0)
.39894228
Whatever mean a normal has just shifts the distribution left or right,
so makes no difference to what the peak density is; hence without loss
of generality we can focus on mean 0.
Whatever SD a normal has, 0/SD is still 0.
Correct me if I'm wrong....
Nick
[email protected]
On 22 November 2013 15:00, Nick Bornschein <[email protected]> wrote:
Hello,
I'm calculating a normal distribution with:
set obs 10000
set seed 2211
gen normal2 = rnormal($mean2, $sd2)
by given mean and sd which I define via global macro.
Is it possible to calculate the maximum density at the mean point?
And more interesting: is it possible to define "xline" until a given point
at the y axis (the maximum density as you can imagine) because I want to add
the mean line with going higher than the maximum density?
Best
-Nick
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