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Re: st: getting Stata to understand the format of the dates
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: getting Stata to understand the format of the dates
Date
Tue, 5 Feb 2013 18:31:17 +0000
Note that this will work too:
gen emonth1=mofd(date(dates, "MDY"))
Note also -- and this is not widely known -- that -daily()- is a
synonym for -date()-.
There is some history there. Apart from say years -- which don't need
special treatment -- Stata had at first just one kind of date, daily
dates, and -date()- was a function to take in string daily dates and
emit numeric daily dates. The name -daily()- does not carry that
ambiguity.
However, -monthly()- is in the same kind of way a function to take in
string monthly dates and emit numeric monthly dates. It is _not_ a
conversion function to take in other kinds of dates and emit numeric
monthly dates, and as Jeph explains, you need -mofd()- for that
purpose.
Nick
On Tue, Feb 5, 2013 at 6:14 PM, Jeph Herrin <[email protected]> wrote:
> This will produce a date variable:
>
> gen edate1=date(dates,"MDY")
> format edate1 %td
>
> and if you want the month
>
> gen emonth1=mofd(edate1)
> format emonth1 %tm
>
> Then, you would declare your data time series data:
>
> tsset emonth1
On 2/5/2013 1:10 PM, Tzaloupas Dimitrov wrote:
>> I have a column with this date format
>>
>>
>> dates
>> 01/07/2009
>> 01/08/2009
>> 01/09/2009
>> 01/10/2009
>> 01/11/2009
>> 01/12/2009
>> 01/01/2010
>> 01/02/2010
>> 01/03/2010
>> 01/04/2010
>> 01/05/2010
>> 01/06/2010
>> 01/07/2010
>>
>>
>> HOw can i get stata understand that this is a time series data set of
>> monthly observations?
>>
>> I tried something like
>>
>> gen edate1 = monthly(dates, "DMY")
>>
>> but it seems that it does not work
>>
>> Any suggestions?
>>
>> I use 64 bit Stata 11
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