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Re: st: Unique Randomization within groups
From
Nick Cox <[email protected]>
To
[email protected]
Subject
Re: st: Unique Randomization within groups
Date
Thu, 31 Jan 2013 12:53:05 +0000
I don't know what your -version- is, but don't worry about that
detail. The point of my code was solely to show something you do
_within groups of 3_.
Something more like
set seed 2803
gen foo = runiform()
bysort cluster_group (foo) : gen random1= _n
Nick
On Thu, Jan 31, 2013 at 12:37 PM, Jonah Rexer <[email protected]> wrote:
> I tried that before, but I can't set an obs lower than 99 on my
> version of stata. Is this normal?
>
> On Thu, Jan 31, 2013 at 3:25 PM, Nick Cox <[email protected]> wrote:
>> Abstracting from the complicated context
>>
>> clear
>> set obs 3
>> set seed <whatever>
>> gen y = runiform()
>> sort y
>> gen wanted = _n
>>
>> gives you -wanted- that is 1, 2, 3. Which observations are assigned 1,
>> 2, 3 is random by virtue of shuffling according to previously
>> generated random numbers. So use the sort order, not the random
>> numbers themselves.
>>
>> (There still is a minute probability of ties. I wouldn't expect that
>> to bite in practice.)
>>
>> On Thu, Jan 31, 2013 at 12:14 PM, Jonah Rexer <[email protected]> wrote:
>>> Hello,
>>>
>>> I am doing a randomization among 3 groups (2 treatment and 1 control) for a
>>> micro experiment.
>>> Our sample is small, N=99 with the unit being a cluster (a group of 2-3
>>> respondents).
>>> I have merged clusters to assign each a random number. But instead of
>>> stratifying, since our sample is so small, I have organized each cluster
>>> into a group of 3 clusters (so 33 groups, each with 3 clusters) based on
>>> our stratification variables.
>>>
>>> What I want to do is assign a random integer, 1-3, within each group. I've
>>> used the command:
>>>
>>> set seed 4109
>>>
>>> bysort cluster_group : gen random1=floor((3-1+1)*runiform()+1)
>>>
>>> The problem is that this doesn't give me a unique number. Within each
>>> group, i need one observation (cluster) to be 1, one to be 2, and one to be
>>> 3. This is why I used bysort, but it doesn't seem to be making any
>>> difference. Is there any way to ensure that the number assigned is unique
>>> within the group?
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