Re: st: prob>chi2 in probit results

[David Hoaglin <dchoaglin@gmail.com>]

Hi, Nola.

Another way to interpret the result of that likelihood-ratio test is
that those 8 predictors, working together, do not account for more of
the variation in pgood than one would expect by chance.

I am not sure why Maarten would consider a model with fewer of those
predictors.  Such a model would not account for any more of the
variation in pgood than all 8 of them.  Perhaps that is not what
Maarten meant.

You have not said enough about the nature of the predictors for me to
guess whether it would help to express any of them differently.

David Hoaglin

On Tue, Jan 29, 2013 at 2:24 PM, nola l <nola0908@gmail.com> wrote:
> Hello,
>
> Please pardon me if my question looks too silly.
>
> I run probit in stata 12 and get following results:
>
> . probit pgood age_kid sex gender parent white  totalkid Ed AGE
>
> Iteration 0:   log likelihood = -148.89225
> Iteration 1:   log likelihood = -145.96563
> Iteration 2:   log likelihood =  -145.9561
> Iteration 3:   log likelihood =  -145.9561
>
> Probit regression                                 Number of obs   =        252
>                                                            LR chi2(8)
>     =       5.87
>                                                            Prob > chi2
>     =     0.6615
> Log likelihood =  -145.9561                Pseudo R2       =     0.0197
>
> Is it correct that as my results showed Prob > chi2     =     0.6615
> which is greater than 0.05, then my model is not a good model and I
> could not really use it?
>
> Is it correct that in order to have a acceptable model, I have to get
> prob>chi2 <0.1? if I got a much bigger number, can I use the model?
> How should I interpret it?
>
> Is there any other command that I can use to test my probit model is
> usable or not?
>
> Thanks in advance for any suggestion that you could give.
>
> Best,
> Nola
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