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Re: st: generate variable versus define scalar, with conditional statement
From
annoporci <[email protected]>
To
[email protected]
Subject
Re: st: generate variable versus define scalar, with conditional statement
Date
Wed, 16 Jan 2013 20:35:57 +0800
Or, he can check if each date occurs at most once,
and simplify his code.
bys date : assert _n == 1
summ open if date == mdy(1,2,2001), meanonly
scalar newscalar = r(mean)
In the present case, date is a unique identifier, but this is a great
addition to my toolkit:
bys date : assert _n == 1
Thanks Paul, I appreciate your feedback very much,
Patrick
---
Patrick Toche.
On Wed, 16 Jan 2013 19:44:55 +0800, Seed, Paul <[email protected]> wrote:
Dear Statalist,
It appears that what Patrick Toche wants is not something that
Stata can do in a single command. This is because what he wants
is not completely clear.
He wants for the system dataset -sp500- to produce a scalar that gives
the value of a particular variable (-open-) at a particular date
chosen by him (-date-).
Depending on the data set , this is an ambiguous request. Suppose the
date
in question occurs more than once, with different values of -open-
attached.
[It doesn't in this case, but it could easily do].
Does he want the minimum, the maximum, the average, or a missing value?
The following covers all these options.
clear all
sysuse sp500
summ open if date == mdy(1,2,2001), meanonly
/// the meanonly option suppresses output, and saves computer time
///by not calculating the standard deviation. It is not essential.
scalar newscalar_mean = r(mean)
scalar newscalar_min= r(min)
scalar newscalar_max= r(max)
if r(n) == 1 scalar newscalar = r(mean)
Or, he can check if each date occurs at most once,
and simplify his code.
bys date : assert _n == 1
summ open if date == mdy(1,2,2001), meanonly
scalar newscalar = r(mean)
BW
Paul T Seed, Senior Lecturer in Medical Statistics,
Division of Women's Health, King's College London
Women's Health Academic Centre, King's Health Partners
(+44) (0) 20 7188 3642.
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--
Patrick Toche.
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