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Re: st: OLS assumptions not met: transformation, gls, or glm as solutions?
From
Ryan Kessler <[email protected]>
To
[email protected]
Subject
Re: st: OLS assumptions not met: transformation, gls, or glm as solutions?
Date
Mon, 17 Dec 2012 10:41:35 -0500
The User's Guide is a great place to start. Maarten's point can also
be illustrated via simulation:
capture program drop ols_sim
program define ols_sim, rclass
version 12
syntax [, NONCONstant robust]
set obs 300
tempvar y x
gen `x'=1 in 1/100
replace `x'=2 in 101/200
replace `x'=3 in 201/300
if "`nonconstant'"!="" gen `y'=rnormal(`x',`x'^2) in 1/300
else gen `y'=rnormal(`x',1) in 1/300
reg `y' `x', `robust'
return scalar beta1=_b[`x']
test `x'=1
return scalar pv=r(p)
end
clear
local reps=1000
cii `reps' `reps'*0.05
local v_lb=round(r(lb), 0.001)
local v_ub=round(r(ub), 0.001)
simulate beta=r(beta1) pv=r(pv), reps(`reps'): ols_sim, nonconstant robust
qui count if pv <= 0.05
local rej_rate=`=r(N)'/`reps'
di "Rejection rate =`rej_rate' [`v_lb',`v_ub']"
Hope this helps!
Ryan
On Mon, Dec 17, 2012 at 10:27 AM, Maarten Buis <[email protected]> wrote:
> On Mon, Dec 17, 2012 at 4:17 PM, Carlo Lazzaro wrote:
>> The main meaning of my example is that you cannot be sure, after invoking
>> -robust-, that heteroskedasticity is automatically removed. In other words,
>> homoskedasticity should be checked graphically even after - robust -.
>
> Robust standard errors do not change the coefficients, just the
> standard errors change. So the predicted values and residuals will
> also remain unchanged after you have specified the -vce(robust)-
> option. The whole point of robust standard errors is not that it
> "solves" in some way for heteroskedasticity, it just makes that
> "assumption" irrelevant. For more, see section 20.20 of the User's
> Guide.
>
> Hope this helps,
> Maarten
>
> ---------------------------------
> Maarten L. Buis
> WZB
> Reichpietschufer 50
> 10785 Berlin
> Germany
>
> http://www.maartenbuis.nl
> ---------------------------------
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