Re: st: Is it possible to use --rename-- with the renumber option to rename variables in reverse order?

[Nick Cox <njcoxstata@gmail.com>]

forval n = 2/11 {
...
}

Nick

On Sun, Oct 28, 2012 at 5:31 AM, Phil Clayton
<philclayton@internode.on.net> wrote:

> foreach n of numlist 2/11 {
>     rename v`n' v`=2011 - `n''
> }

On 28/10/2012, at 15:16, Aaron Kirkman <ak1795mailserv@gmail.com> wrote:

>> Is there a simpler way to do this in a loop? (I realise this solution
>> is fairly simple, but I want to make sure I didn't miss something).
>>
>> ****
>> clear
>> input v2 v3 v4 v5 v6 v7 v8 v9 v10 v11
>> 309 418 333 153 259 172 359 319 440 317
>> end
>>
>> foreach v of varlist v2-v11 {
>>    local year = 2011 - real(subinstr("`v'", "v", "", .))
>>    rename `v' v`year'
>> }
>> ****

On Sat, Oct 27, 2012 at 10:49 PM, kantor.d@att.net <kantor.d@att.net> wrote:

>>> I don't know if you can do that within the capabilities of -rename- alone, but it can be done in a loop.

Aaron Kirkman

>>> I have a dataset with variables v2 through v11, in that order. I'd
>>> like to rename the variables v2009, v2008, v2007, etc. down to v2000.
>>> In other words, v2 = v2009, v3 = v2008, etc. Is there a way to do this
>>> with the --rename-- command in Stata 12.1 ? Perhaps some variation on:
>>>
>>> ****
>>> rename v* v#, renumber(2009)
>>> ****
>>>
>>> which gives me v2 = 2009, v3 = 2010, etc. In essence, I'm trying to
>>> use a similar behaviour but in reverse order. I know that reversing
>>> the order of the data set and using --rename-- in a similar fashion
>>> will work:
>>>
>>> ****
>>> order v11 v10 v9 v8 v7 v6 v5 v4 v3 v2
>>> rename v* v#, renumber(2000)
>>> ****
>>>
>>> I'm curious if there is a more general way, since I don't think I can
>>> specify a varlist in reverse order, i.e. v11 - v2 will not work unless
>>> the variables are already in that format.
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