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RE: st: gamma
From
Jason Rosenberg <[email protected]>
To
"[email protected]" <[email protected]>
Subject
RE: st: gamma
Date
Thu, 11 Oct 2012 12:45:47 +0000
When I type in: help gamma, I get:
Out-of-date command
As of Stata 8.0, the cox, weibull[het], lnormal[het], gamma[het], llogist,
llogistic[het], ereg[het], and gompertz[het] commands are out of date.
The replacement for cox is stcox.
The replacement for weibull[het], lnormal[het], gamma[het], llogist,
llogistic[het], ereg[het], and gompertz[het] is streg.
I read through those but to no avail.
In any case I used R to do the gamma part.
If possible could you tell how to run this for a continuous variable in place of the 6, I did it for discreet variables, as in:
egen number = seq()
then:
gen prob=(v/gamma(alpha/v))*(beta^(2*alpha)/(number+11.2)^(alpha+1))*exp(-(beta^2/(number+11.2))^v)
but I need a curve instead of a simple scatter plot. If you could direct me to the relevant help files that would suffice..
________________________________________
From: [email protected] [[email protected]] on behalf of Nick Cox [[email protected]]
Sent: Thursday, October 11, 2012 12:31 PM
To: [email protected]
Subject: Re: st: gamma
There is no function -gamma()-, largely I suspect because its values
become very big.
There is a function -lngamma()-, so you would need -exp(lngamma())-.
Almost all of this can be established by looking at the help for -functions-.
Nick
On Thu, Oct 11, 2012 at 1:25 PM, Jason Rosenberg <[email protected]> wrote:
> hi
> I an attempting to put this equation into stata:
>
> gen prob=(v/gamma(alpha/v))*(beta^(2*alpha)/(6+11.2)^(alpha+1))*exp(-(beta^2/(6+11.2))^v)
> where v, alpha, and beta are predefined my the user
> and I get :
> unknown function gamma()
>
> Is there another syntax I should know for gamma?
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