Re: st: differentiating between groups of records with same date

[Nick Cox <njcoxstata@gmail.com>]

bysort patient_no diag_date: gen freq = _N

See also

SJ-2-1  pr0004  . . . . . . . . . . Speaking Stata:  How to move step by: step
        . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .  N. J. Cox
        Q1/02   SJ 2(1):86--102                                  (no commands)
        explains the use of the by varlist : construct to tackle
        a variety of problems with group structure, ranging from
        simple calculations for each of several groups to more
        advanced manipulations that use the built-in _n and _N


Nick

On Mon, Jul 30, 2012 at 10:20 AM, Tim Evans <Tim.Evans@wmciu.nhs.uk> wrote:
> Hi all,
>
> I have a group of patients who are in a dataset of cancers. Each patient may have more than one cancer diagnosed, and so may be present in my dataset a number of times. Each patient has a unique patient identifier, and each cancer has a unique cancer identifier. Each row of data is cancer specific, but does contain the patient identifier. It is possible that a patient has 2 cancers diagnosed on the same day in my dataset. What I would like to do is generate a flag next to each record to show against each cancer the number of cancers diagnosed on the same day.
>
> My data are like this:
>
> patient_no              cancer_no       diag_date       surgery_date
> 9512834         0484360 21may1994       21may1994
> 9512834         0484358 21may1994       21may1994
> 9512834         0483234 26apr2000       21may2000
> 9512834         0483233 26apr2000
> 0000057         0000057 19jul2009       19jul2009
> 0000060         0000060 02nov2009       24nov2009
> 0000074         0000074 21sep2009       22nov2009
>
>
> For example, patient 9512834 had 2 cancers diagnosed on 21may1994 and so for cancer_no 0484360 and 0484358, I would like to generate a new variable with the value 2 against each record. Similiarly patient 0000057 has only one cancer diagnosed, and so the new variable would contain 1.
>
>

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