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st: RE: RE: imputing dates into a string date
From
Tim Evans <[email protected]>
To
"'[email protected]'" <[email protected]>
Subject
st: RE: RE: imputing dates into a string date
Date
Thu, 7 Jun 2012 15:45:36 +0100
Nick, Daniel, Steve,
Many thanks for your invaluable comments and tips. Nicks version won out at the finish as it cleverly picked out the fact (without me posting!!) that I might have missing month to which I wouldn't want to impute a value for. It also converted into a numeric date as well.
Thanks once again.
Best wishes
Tim
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of Nick Cox
Sent: 07 June 2012 15:32
To: '[email protected]'
Subject: st: RE: imputing dates into a string date
Steve Samuels and I wrote a Tip on imputing day of month. (It arose out of a Statalist thread.)
SJ-12-1 dm0062 . . . . . . . . . Stata tip 105: Daily dates with missing days
. . . . . . . . . . . . . . . . . . . . . S. J. Samuels and N. J. Cox
Q1/12 SJ 12(1):159--161 (no commands)
presents strategies for dealing with daily dates where
some observations only provide the month and year
Let's suppose that you want to impute "15" for "XX". (The import of the Tip just cited is that there are methods that are often better.)
Then your code could be
gen xxflag = substr(date, 1, 2) == "XX"
gen double dx2 = cond(xxflag, date(subinstr(dx, "XX", "15",1), "DMY"), date(dx, "DMY"))
The variable -xxflag- is not absolutely needed for the bare -generate-. It is added to document where you imputed.
Nick
[email protected]
Tim Evans
I have dates in the form DMY in a string variable
i.e. 22/01/2010
I am generating numerical dates using the following code:
generate double dx2 = date(dx, "DMY")
format %tdDD/NN/CCYY dx2
This is working fine, until I come across a date that actually starts like this:
xx/01/2010
Then my code to generate a date returns a blank. What I would like to do is add in something that allows me to evaluate whether the day is xx and if so, insert 01.
Am I to assume I need something like regexm
if regexm(dx2, "^XX") == 1
replace"XX" = 01
else
generate double dx2 = date(dx, "DMY")
format %tdDD/NN/CCYY dx2
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