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RE: st: How to standardize a variable with a define mean
From
Nick Cox <[email protected]>
To
"'[email protected]'" <[email protected]>
Subject
RE: st: How to standardize a variable with a define mean
Date
Wed, 1 Feb 2012 11:23:18 +0000
Maarten is quite correct here in fixing your syntax, but note that -egen- is not needed here given that you have already -summarized- BMI.
su BMI
gen stdmi = (BMI - r(mean)) / r(sd)
That way the whole business of putting value of r(mean) into a scalar, only to have to take it out again, is avoided.
Even going the -egen- route the -scalar- is not needed and you don't even need to feed r(mean) to -egen- as by default the -std()- function works with the mean and standard deviation of the expression specified, here a variable name.
. egen stdmpg1 = std(mpg)
. su mpg
Variable | Obs Mean Std. Dev. Min Max
-------------+--------------------------------------------------------
mpg | 74 21.2973 5.785503 12 41
. gen stdmpg2 = (mpg - r(mean)) / r(sd)
. su stdmpg*
Variable | Obs Mean Std. Dev. Min Max
-------------+--------------------------------------------------------
stdmpg1 | 74 -7.00e-09 1 -1.606999 3.40553
stdmpg2 | 74 -7.00e-09 1 -1.606999 3.40553
So, the problem needs one line or two, depending on whether you choose convenience or Stata minimalism, but not more.
Nick
[email protected]
Maarten Buis
On Wed, Feb 1, 2012 at 10:44 AM, Alberto R Osella wrote:
> I want to standardize a variable (BMI) with a given mean value. I've
> obtained that value from a -summarize- command, that is r(mean).
> Now I want to pass the value of r(mean) to the egen command. Here the
> commands and the error returned by Stata.
>
> . sum BMI
> . scalar meanbmi=r(mean)
> . display meanbmi
> 25.8435
> . egen stdbmi=std(BMI), mean(meanbmi) std(1)
> option mean() incorrectly specified
> r(198);
try:
egen stdbmi=std(BMI), mean(`=meanbmi') std(1)
The trick is that meanbmi is the name of a scalar while the -mean()-
option expects a number. By surrounding that scalar name with " `= "
and " ' " you are forcing Stata to first evaluate the scalar name,
resulting in a number, which is exactly what the -mean()- option
wanted.
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