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st: Why the square of a negative number is still negative
From
"Tiago V. Pereira" <[email protected]>
To
[email protected]
Subject
st: Why the square of a negative number is still negative
Date
Fri, 16 Dec 2011 14:49:27 -0200 (BRST)
Thank yo very much, Austin and João Ricardo, for your extremely useful
explanations.
Tiago
----------------------------------------
Dear statalisters,
Can someone explain why is this happening?:
local x = -2
*/Approach A:
dis (`x'^2)*(5)
*/Approach B:
dis (`x'*`x')*(5)
*/Approach C:
dis ((`x')^2)*(5)
My output is:
. dis (`x'^2)*(5)
-20
. */Approach B:
. dis (`x'*`x')*(5)
20
. */Approach C:
. dis ((`x')^2)*(5)
20
Do I need vacations? (Am I forgetting something very simple from
mathematics?)
All the best,
Tiago
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