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Re: st: Mata looping question


From   Anna Reimondos <[email protected]>
To   [email protected]
Subject   Re: st: Mata looping question
Date   Tue, 18 Oct 2011 21:09:01 +1100

Hi Maarten
Thanks very much for the reply that is very helpful..however I was
hoping to shift the elements across the columns the other way if that
makes sense.

E.g. if matrix a is:

    c1  c2  c3
r1   1   0   0
r2   0   2   1
r3   0   1   0
r4   0   0   0

then matrix b I want to look like:

    c1  c2  c3
r1   2   1   .
r2   1   0   .
r3   0   0   .
r4   .   .   .

(To give a bit of context, the data I am working with has ages of
women in the row e.g. 15, 16...45 and number of children at different
ages e.g. 0,1,2,...15 in the columns . I am reverse ageing the data.
So at r2,c2 it means in year T a woman aged 16 had 2 children aged 2.
The b matrix is trying to get at year T-1. In that case she was 15 and
had 2 children aged 1)

Cheers
Anna


On Tue, Oct 18, 2011 at 8:54 PM, Maarten Buis <[email protected]> wrote:
> On Tue, Oct 18, 2011 at 11:37 AM, Anna Reimondos wrote:
>> For example if I have one original matrix called 'a'
>>
>> matrix a=(1,0,0\0,2,1\0,1,0\0,0,0)
>> matrix list a
>>
>> I then want to create another matrix 'b' which is equal to 'a' but
>> where every element has been shifted up one row and across one column.
>
> I would not do that with a loop:
>
> *------------- begin example ----------------
> mata
> a=(1,0,0\0,2,1\0,1,0\0,0,0)
> b = J(5,1,0), (a \ J(1,3,0))
> b
> end
> *----------- end example ----------------
> (For more on examples I sent to the Statalist see:
> http://www.maartenbuis.nl/example_faq )
>
> Hope this helps,
> Maarten
>
> --------------------------
> Maarten L. Buis
> Institut fuer Soziologie
> Universitaet Tuebingen
> Wilhelmstrasse 36
> 72074 Tuebingen
> Germany
>
>
> http://www.maartenbuis.nl
> --------------------------
> *
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>

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