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Re: st: Mata looping question
From
Anna Reimondos <[email protected]>
To
[email protected]
Subject
Re: st: Mata looping question
Date
Tue, 18 Oct 2011 21:09:01 +1100
Hi Maarten
Thanks very much for the reply that is very helpful..however I was
hoping to shift the elements across the columns the other way if that
makes sense.
E.g. if matrix a is:
c1 c2 c3
r1 1 0 0
r2 0 2 1
r3 0 1 0
r4 0 0 0
then matrix b I want to look like:
c1 c2 c3
r1 2 1 .
r2 1 0 .
r3 0 0 .
r4 . . .
(To give a bit of context, the data I am working with has ages of
women in the row e.g. 15, 16...45 and number of children at different
ages e.g. 0,1,2,...15 in the columns . I am reverse ageing the data.
So at r2,c2 it means in year T a woman aged 16 had 2 children aged 2.
The b matrix is trying to get at year T-1. In that case she was 15 and
had 2 children aged 1)
Cheers
Anna
On Tue, Oct 18, 2011 at 8:54 PM, Maarten Buis <[email protected]> wrote:
> On Tue, Oct 18, 2011 at 11:37 AM, Anna Reimondos wrote:
>> For example if I have one original matrix called 'a'
>>
>> matrix a=(1,0,0\0,2,1\0,1,0\0,0,0)
>> matrix list a
>>
>> I then want to create another matrix 'b' which is equal to 'a' but
>> where every element has been shifted up one row and across one column.
>
> I would not do that with a loop:
>
> *------------- begin example ----------------
> mata
> a=(1,0,0\0,2,1\0,1,0\0,0,0)
> b = J(5,1,0), (a \ J(1,3,0))
> b
> end
> *----------- end example ----------------
> (For more on examples I sent to the Statalist see:
> http://www.maartenbuis.nl/example_faq )
>
> Hope this helps,
> Maarten
>
> --------------------------
> Maarten L. Buis
> Institut fuer Soziologie
> Universitaet Tuebingen
> Wilhelmstrasse 36
> 72074 Tuebingen
> Germany
>
>
> http://www.maartenbuis.nl
> --------------------------
> *
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>
*
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