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Re: st: reading dataset if (Away)
From
"Seyi Soremekun" <[email protected]>
To
<[email protected]>
Subject
Re: st: reading dataset if (Away)
Date
Wed, 21 Sep 2011 23:49:15 +0100
I am away from the 21st September until the 12th October. Please direct any urgent enquiries to Linda Vesel ([email protected]).
Seyi
>>> Austin Nichols <[email protected]> 09/21/11 23:48 >>>
Emmanuelle Lavaine <[email protected]>:
Try
use if inlist(substr(diagp,1,1), "I", "J") using dataset.dta
On Wed, Sep 21, 2011 at 6:12 PM, Nick Cox <[email protected]> wrote:
> You are reaching towards some kind of regular expression test but ==
> is a test for equality.
>
> use dataset.dta if inlist(substr(diagp,1,1), "I", "J")
>
> use dataset.dta if substr(diagp,1,1) == "I" | substr(diagp,1,1) == "J"
>
> Regular expressions are also possible here:
>
> . di regexm("Janvier", "^[IJ]")
> 1
>
> . di regexm("jeunesse", "^[IJ]")
> 0
>
> . di regexm("Jeunesse", "^[IJ]")
> 1
>
> use dataset.dta if regexm(diagp, "^[IJ]")
>
> On Wed, Sep 21, 2011 at 10:46 PM, Emmanuelle Lavaine
> <[email protected]> wrote:
>
>> I have a huge dataset and I would like to get rid of some observations
>> when opening it.
>> I want to open my dataset only if the first character corresponds to
>> 'I' or 'J'
>> for the string variable 'diagp', I have something like:
>>
>> diagp
>> I236
>> I256
>> I52
>> J46
>> J856
>> H343
>> etc..
>>
>> I tried:
>> use 'dataset.dta' if diagp=="[I-J]*"
>>
>> But I am doing something wrong and I can't figurate it out.
>
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