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st: pmg &mg based on Hausman
From
Nahla Samargandi <[email protected]>
To
"[email protected]" <[email protected]>
Subject
st: pmg &mg based on Hausman
Date
Mon, 29 Aug 2011 13:23:09 +0100
Dear stata group,
I could solve my previous problem regarding xtpmg. thanks for helping.
and I have another question regarding Hausman test to compare between MG and PMG
I run Hausman test below, and I would like firstly to make sure is this the right way to compare pmg with mg based on Hausman test, second, the p value I got is it indicate to the fails to reject the restriction of common long-run coefficecnts . Hence, the MG estimator is not as informative as the PMG estimator or the opposite ? third, how i can see the p value for each coefficient separately ?
hausman mg pmg,sigmamore
---- Coefficients ----
| (b) (B) (b-B) sqrt(diag(V_b-V_B))
| mg pmg Difference S.E.
-------------+----------------------------------------------------------------
L2.lntrade~p | -15.99317 6.072908 -22.06608 38.81535
education | -58.71332 -8.795231 -49.91809 67.2527
L.lnca | 60.09664 -2.920407 63.01705 44.75497
lngov | 7.75185 -3.248477 11.00033 67.8732
fd | -3.280872 2.16955 -5.450422 23.96994
------------------------------------------------------------------------------
b = consistent under Ho and Ha; obtained from xtpmg
B = inconsistent under Ha, efficient under Ho; obtained from xtpmg
Test: Ho: difference in coefficients not systematic
chi2(5) = (b-B)'[(V_b-V_B)^(-1)](b-B)
= 3.34
Prob>chi2 = 0.6472 ( if this is > 0.05) (i.e insignificant use PMG )
Best regards
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