Re: st: Creating household id for groups of persons

[Friedrich Huebler <fhuebler@gmail.com>]

Hans,

I think I misread your question. If I understand correctly, persons 1,
2 and 3 live in one household and persons 4 and 5 live in another
household.

Do you have at least one contract in each household that covers all
household members, as in your example contract 123 in the first
household?

Friedrich

On Wed, Jul 6, 2011 at 7:50 AM, Friedrich Huebler <fhuebler@gmail.com> wrote:
> Hans,
>
> I would add one more question: How do you know that the persons with
> contract numbers 123, 456 and 678 live in the same household? Do you
> have another variable that you are not showing us that contains this
> information?
>
> Friedrich
>
> On Wed, Jul 6, 2011 at 7:27 AM, Nick Cox <n.j.cox@durham.ac.uk> wrote:
>> How do you know that the resulting groups would be disjoint?
>>
>> Nick
>> n.j.cox@durham.ac.uk
>>
>> Hans Meier
>>
>> No, I wished it was that easy.
>>
>> With
>> egen group = group(contract)    you get:
>>
>>  contract |    id       |  household_id
>> ___________________________
>>  123        |   1        |   1  <-
>>  123        |   2        |   1
>>  123        |   3        |   1
>>  456        |   4        |   2
>>  456        |   5        |   2
>>  678        |   1        |   3  <-
>>
>> As you can see, now id "1" has two different household id's, "1" at contract "123" and "3" at contract "678".
>>
>> But I want to put all id's who are connected in any contract in the same household, so that the household_id in contract "678" is also "1", because id "1" already belongs to household "1" from contract "123".
>>
>> Maybe an example makes it clearer:
>>
>> Imagine contract "123" beeing a liability-insurance for a mother, father and child (id's 2, 1 and 3), who are household 1.
>> The father (id 1) also has a car insurance (contract 678), and of course this contract also belongs to household 1.
>>
>> But anyway, thank you for your fast reply!
>>
>> Von: "Nick Cox" <njcoxstata@gmail.com>
>>
>>>If I understand this correctly, -contract- is already such an
>>>identifier. You can use
>>>
>>>egen group = group(contract)
>>>
>>>to get a tidy equivalent with values 1 up.
>>>
>>>Nick
>>>
>>>On Wed, Jul 6, 2011 at 8:23 AM, Hans Meier <mr.hans.meier@web.de> wrote:
>>>
>>>> I'm trying to create an id-variable for groups of persons.
>>>>
>>>> My data looks like this:
>>>>
>>>>
>>>> contract |    id
>>>> ___________
>>>> 123        |   1
>>>> 123        |   2
>>>> 123        |   3
>>>> 456        |   4
>>>> 456        |   5
>>>> 678        |   1
>>>>
>>>> There are different insurance-contracts, and many people (id's) can be part of one contract.
>>>>
>>>> Now I need a household id, which groups the people who have contracts together, like this:
>>>>
>>>>
>>>> contract |    id       |  household_id
>>>> ___________________________
>>>> 123        |   1        |   1
>>>> 123        |   2        |   1
>>>> 123        |   3        |   1
>>>> 456        |   4        |   2
>>>> 456        |   5        |   2
>>>> 678        |   1        |   1
>>>>
>>>> The problem is, as you can see in my example, that its's not always the same people having contracts together, like id "1" has the contract "678" alone, but he belongs to household_id "1".
>>>>
>>>> How can I create this household id?
>

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